大约有 23,000 项符合查询结果（耗时：0.0375秒） [XML]
Is there a Wikipedia API?
...
JWPL - Java-based Wikipedia Library -- An application programming interface for Wikipedia
http://code.google.com/p/jwpl/
share
...
How to convert .crt to .pem [duplicate]
...fect, thanks. Seems some crt files are binary (DER) encoded and others are base64 encoded like pem.
– Brad Hein
Jul 6 '18 at 12:04
...
Is there a way to only install the mysql client (Linux)?
...
or Debian based distros
– CTodea
Jul 26 '18 at 13:54
1
...
How to run a process with a timeout in Bash? [duplicate]
...ommand line arguments. See an alternate solution posted by @ArjunShankar . Based on it you can encapsulate that boiler-plate code and create your own portable timeout script or small C app that does the same thing.
share
...
How to fix apt-get: command not found on AWS EC2? [closed]
...
Try replacing apt-get with yum as Amazon Linux based AMI uses the yum command instead of apt-get.
share
|
improve this answer
|
follow
...
BSON与JSON的区别 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...“byte array”数据类型。这使得二进制的存储不再需要先base64转换后再存成JSON。大大减少了计算开销和数据大小。
当然，在有的时候，BSON相对JSON来说也并没有空间上的优势，比如对{“field”:7}，在JSON的存储上7只使用了一个字...
二进制文件的读写 - App Inventor 2 中文网 - 清泛IT社区，为创新赋能！
...
如果想要保存二进制到文件，可以考虑转换成 ascii 或 base64 化，然后通过文件管理器保存为文件，具体请帮助，拓展文档找相应的拓展即可实现。
也可以考虑这个拓展，直接可以保存二进制数据到文件，拓展请自行下载：
...
What would cause an algorithm to have O(log log n) complexity?
...er algorithm (but still rather hard) with running time O(n log log n), the base of algorithm is as follow (just very rough description, and I'd offer to skip understanding this part and read the other part of the answer):
divide graph into the parts of size O(log n/(log log n)) with some restricti...
Expert R users, what's in your .Rprofile? [closed]
...he function (e.g. utils::head) otherwise it won't work.
# aliases
s <- base::summary
h <- utils::head
n <- base::names
EDIT: to answer your question, you can use the colorout package to have different colors in the terminal. Cool! :-)
...
Windows下 C++网络延时检测 - C/C++ - 清泛网 - 专注C/C++及内核技术
... Time = 0; // microsecond
unsigned long Sum = 0; //
char hostIpBuf[64] = { 0L }; //
struct in_addr iaDest; // Internet address structure
LPHOSTENT pHost = NULL; // Pointer to host entry structure
DWORD *dwAddress = NULL; // IP Address
IPINFO ipInfo; // IP Options structur...