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How to convert NSNumber to NSString
So I have an NSArray "myArray" with NSNumber s and NSString s. I need them in another UIView so i go like this:
7 Ans...
How to call a method with a separate thread in Java?
...start() on it. start tells the JVM to do the magic to create a new thread, and then call your run method in that new thread.
public class MyRunnable implements Runnable {
private int var;
public MyRunnable(int var) {
this.var = var;
}
public void run() {
// code i...
How to find the duration of difference between two dates in java?
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try the following
{
Date dt2 = new DateAndTime().getCurrentDateTime();
long diff = dt2.getTime() - dt1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1...
Why should I use a semicolon after every function in javascript?
...seen different developers include semicolons after functions in javascript and some haven't. Which is best practice?
9 Answ...
CSS: Truncate table cells, but fit as much as possible
...on! Better late than never, right? After all this is an excellent question and Google is all over it. I didn't want to settle for a javascript fix because I find the slight jitter of things moving around after the page is loaded to be unacceptable.
Features:
No javascript
No fixed-layout
No weigh...
PostgreSQL delete all content
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Use the TRUNCATE TABLE command.
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Append integer to beginning of list in Python [duplicate]
I have an integer and a list. I would like to make a new list of them beginning with the variable and ending with the list.
Writing a + list I get errors. The compiler handles a as integer, thus I cannot use append, or extend either.
How would you do this?
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Path.Combine for URLs?
Path.Combine is handy, but is there a similar function in the .NET framework for URLs ?
40 Answers
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Is it possible to “await yield return DoSomethingAsync()”
...re regular iterator blocks (i.e. "yield return") incompatible with "async" and "await"?
9 Answers
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Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array
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You could sort the array and then run through it and then see if the next (or previous) index is the same as the current. Assuming your sort algorithm is good, this should be less than O(n2):
const findDuplicates = (arr) => {
let sorted_ar...