大约有 46,000 项符合查询结果（耗时：0.0446秒） [XML]
What is the difference between precision and scale?
...: Precision 4, scale 2 - will fail any number > 99.9999..; try: select cast (99.99999 as NUMBER(4,2)) from dual; //OK; select cast (100.9 as NUMBER(4,2)) from dual; //FAIL;
– Jama Djafarov
Mar 6 '15 at 17:47
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What's the difference between IEquatable and just overriding Object.Equals()?
...it as much but the IEquatable<T> implementation does let you avoid a cast from System.Object which can make a difference if it's called frequently.
As noted on Jared Parson's blog though, you still must implement the Object overrides.
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How to apply bindValue method in LIMIT clause?
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I remember having this problem before. Cast the value to an integer before passing it to the bind function. I think this solves it.
$fetchPictures->bindValue(':skip', (int) trim($_GET['skip']), PDO::PARAM_INT);
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How to return only the Date from a SQL Server DateTime datatype
...har(30), @Date, 101) or something similar. See SQL Server Books Online • Cast and Convert for more info.
– ErikE
Aug 17 '12 at 22:03
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How do you specify a byte literal in Java?
...ered an integer (or long if followed by a "L"), so you must explicitly downcast it to a byte to pass it as a parameter. As far as I know there is no shortcut.
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JSON Array iteration in Android/Java
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You are using the same Cast object for every entry.
On each iteration you just changed the same object instead creating a new one.
This code should fix it:
JSONArray jCastArr = jObj.getJSONArray("abridged_cast");
ArrayList<Cast> castList= n...
How can I convert a long to int in Java?
...ted, in Java 8:
Math.toIntExact(value);
Original Answer:
Simple type casting should do it:
long l = 100000;
int i = (int) l;
Note, however, that large numbers (usually larger than 2147483647 and smaller than -2147483648) will lose some of the bits and would be represented incorrectly.
For ...
How do I make the method return type generic?
...nimal> T callFriend(String name, Class<T> type) {
return type.cast(friends.get(name));
}
Then call it as such:
jerry.callFriend("spike", Dog.class).bark();
jerry.callFriend("quacker", Duck.class).quack();
This code has the benefit of not generating any compiler warnings. Of course ...
Test if object implements interface
... +1 The second one is better because you will probably end up needing to cast afterward with the first one thus giving you two casts ("is" and then an explicit cast). With the second approach you only cast once.
– Andrew Hare
Jan 4 '09 at 6:02
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How do I perform an insert and return inserted identity with Dapper?
...gle<int>( @"
INSERT INTO [MyTable] ([Stuff]) VALUES (@Stuff);
SELECT CAST(SCOPE_IDENTITY() as int)", new { Stuff = mystuff});
Note that on more recent versions of SQL Server you can use the OUTPUT clause:
var id = connection.QuerySingle<int>( @"
INSERT INTO [MyTable] ([Stuff])
OUTPUT ...