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Rebuild IntelliJ project indexes
IntelliJ IDEA 10.5.1 is reporting zero usages for all method, classes etc.
2 Answers
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Detecting CTRL+C in Node.js
...al");
if (i_should_exit)
process.exit();
});
Edit: doesn't work on Windows without a workaround. See here
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Update value of a nested dictionary of varying depth
I'm looking for a way to update dict dictionary1 with the contents of dict update wihout overwriting levelA
24 Answers
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What's the cause of this FatalExecutionEngineError in .NET 4.5 beta? [closed]
...rally. Suddenly my code thew a very nasty-sounding FatalExecutionEngineError exception. I spent a good 30 minutes trying to isolate and minimize the culprit sample. Compile this using Visual Studio 2012 as a console app:
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How do I concatenate two strings in C?
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C does not have the support for strings that some other languages have. A string in C is just a pointer to an array of char that is terminated by the first null character. There is no string concatenation operator in C.
Use strcat to concatenate tw...
Using sed, how do you print the first 'N' characters of a line?
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Actually on a Cygwin system I'm working on now cut doesn't cut it while sed does.
– kqw
Feb 17 '16 at 9:52
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Simplest SOAP example
... '<soapenv:Envelope ' +
'xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" ' +
'xmlns:api="http://127.0.0.1/Integrics/Enswitch/API" ' +
'xmlns:xsd="http://www.w3.org/2001/XMLSchema" ' +
'xmlns:soapenv="http://sc...
in javascript, how can i get the last character in a string [duplicate]
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Note: this was introduced in es5, so not supported in very old browsers, eg. IE6.
– programmer5000
Feb 23 '17 at 18:36
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Difference between onCreateView and onViewCreated in Fragment
...se two methods? When I create a TextView, should I use one over the other for performance?
9 Answers
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Simple way to repeat a String in java
I'm looking for a simple commons method or operator that allows me to repeat some String n times. I know I could write this using a for loop, but I wish to avoid for loops whenever necessary and a simple direct method should exist somewhere.
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