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renderpartial with null model gets passed the wrong type
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Andrew I think the problem you are getting is a result of the RenderPartial method using the calling (view)'s model to the partial view when the model you pass is null.. you can get around this odd behavior by doing:
<% H...
Can you detect “dragging” in jQuery?
...drags on the "a" element. Just look for a certain amount of change in an x and y mousemove event.
– Ash Blue
May 21 '14 at 23:45
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LINQ query on a DataTable
I'm trying to perform a LINQ query on a DataTable object and bizarrely I am finding that performing such queries on DataTables is not straightforward. For example:
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Showing which files have changed between two revisions
I want to merge two branches that have been separated for a while and wanted to know which files have been modified.
18 Ans...
access denied for load data infile in MySQL
...AD DATA INFILE '{$file}' INTO TABLE {$table}
Add LOCAL to your statement and the permissions issue should go away. Like so:
LOAD DATA LOCAL INFILE '{$file}' INTO TABLE {$table}
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Footnotes for tables in LaTeX
...difficulty in LaTeX.
The problem is how to do layout with floats (figures and tables, an similar objects) and footnotes. In particular, it is hard to pick a place for a float with certainty that making room for the associated footnotes won't cause trouble. So the standard tabular and figure environ...
What is the !! (not not) operator in JavaScript?
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This is used to convert truthy values to boolean true, and falsy values too boolean false.
– thetoolman
Jul 16 '12 at 3:53
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How to improve performance of ngRepeat over a huge dataset (angular.js)?
I have a huge dataset of several thousand rows with around 10 fields each, about 2MBs of data. I need to display it in the browser. Most straightforward approach (fetch data, put it into $scope , let ng-repeat="" do its job) works fine, but it freezes the browser for about half of a minute when i...
How to hide elements without having them take space on the page?
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Try setting display:none to hide and set display:block to show.
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How to split a comma-separated string?
...ill split the string according to (in this case) delimiter you are passing and will return an array of strings.
However, you seem to be after a List of Strings rather than an array, so the array must be turned into a list by using the Arrays.asList() utility. Just as an FYI you could also do somet...