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Why '&&' and not '&'?
...not computed using bitwise calculations. The result is basically looked up based on the values of the two operands, because the number of possibilities is so small.
Because both values are used for the lookup, this implementation isn't short-circuiting.
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How do I get the application exit code from a Windows command line?
... and want to see what its return code is (since it returns different codes based on different errors).
7 Answers
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How to print Boolean flag in NSLog?
...ol value: %d",b);
or
NSLog(@"bool %s", b ? "true" : "false");
On the bases of data type %@ changes as follows
For Strings you use %@
For int you use %i
For float and double you use %f
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SFTP in Python? (platform independent)
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There's also code.google.com/p/pysftp which is based on Paramiko, but easier to use
– franzlorenzon
Feb 8 '13 at 14:08
1
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What does string::npos mean in this code?
...can not be negative... real meaning is max_index, 18446744073709551615 for 64 bit size_t
– NoSenseEtAl
Sep 4 '14 at 12:33
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How to generate a random string of a fixed length in Go?
...te, n)
for i := range b {
b[i] = letterBytes[rand.Int63() % int64(len(letterBytes))]
}
return string(b)
}
This works and is significantly faster, the disadvantage is that the probability of all the letters will not be exactly the same (assuming rand.Int63() produces all 63-bit ...
Deep Learning（深度学习）学习笔记整理系列之（二） - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图：一个图可以通过用64种正交的edges（可以理解成正交的基本结构）来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献，因此均为0 。
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Deep Learning（深度学习）学习笔记整理系列之（二） - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图：一个图可以通过用64种正交的edges（可以理解成正交的基本结构）来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献，因此均为0 。
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Deep Learning（深度学习）学习笔记整理系列之（二） - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图：一个图可以通过用64种正交的edges（可以理解成正交的基本结构）来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献，因此均为0 。
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Deep Learning（深度学习）学习笔记整理系列之（二） - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图：一个图可以通过用64种正交的edges（可以理解成正交的基本结构）来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献，因此均为0 。
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