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SQL Server : GROUP BY clause to get comma-separated values [duplicate]
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try this:
SELECT ReportId, Email =
STUFF((SELECT ', ' + Email
FROM your_table b
WHERE b.ReportId = a.ReportId
FOR XML PATH('')), 1, 2, '')
FROM your_table a
GROUP BY ReportId
SQL fiddle demo
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How to identify all stored procedures referring a particular table
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SELECT Name
FROM sys.procedures
WHERE OBJECT_DEFINITION(OBJECT_ID) LIKE '%TableNameOrWhatever%'
BTW -- here is a handy resource for this type of question: Querying the SQL Server System Catalog FAQ
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How to select label for=“XYZ” in CSS?
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The selector would be label[for=email], so in CSS:
label[for=email]
{
/* ...definitions here... */
}
...or in JavaScript using the DOM:
var element = document.querySelector("label[for=email]");
...or in JavaScript using...
SQL Server Output Clause into a scalar variable
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But then I'd have to "SELECT @someInt = ID FROM @ID". I wanted to know if its possible to skip that extra step (and intermediary table variable) if all I need is the resulting int.
– Benoittr
Apr 5 '11 at 21:...
AngularJS: how to implement a simple file upload with multipart form?
...tags so you have to do it in a "native-way" that pass the all (eventually) selected files from the user.
controller
$scope.uploadFile = function(files) {
var fd = new FormData();
//Take the first selected file
fd.append("file", files[0]);
$http.post(uploadUrl, fd, {
withCr...
select and update database record with a single queryset
How do I run an update and select statements on the same queryset rather than having to do two queries:
- one to select the object
- and one to update the object
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iOS 5 Best Practice (Release/retain?)
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@Dan: You're not joking it can be selectively turned off? Please give a link, that is important to me! :D
– sudo rm -rf
Jun 10 '11 at 15:43
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Directive isolate scope with ng-repeat scope in AngularJS
...moved:
<li ng-repeat="name in names"
ng-class="{ active: $index == selected }"
ng-click="selected = $index">
{{$index}}: {{name.first}} {{name.last}}
</li>
Here is a JSFiddle demonstrating that it won't work. You get the exact same results as in your directive.
Why doesn'...
What Does Question Mark Mean in Xcode Project Navigator?
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You can add to source control by selecting the untracked files
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java.lang.ClassNotFoundException: org.springframework.web.context.ContextLoaderListener
...rties (e.g., right-click on the project's name in the project explorer and select "Properties").
Select "Deployment Assembly".
Click the "Add..." button on the right margin.
Select "Java Build Path Entries" from the menu of Directive Type and click "Next".
Select "Maven Dependencies" from the Java B...