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How to create a cron job using Bash automatically without the interactive editor?
Does crontab have an argument for creating cron jobs without using the editor (crontab -e). If so, What would be the code create a cronjob from a Bash script?
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Is Enabling Double Escaping Dangerous?
I have an ASP.NET MVC application with a route that allows searching for stuff via /search/.
4 Answers
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Spring Boot application as a Service
...utable jar as a Service in the Linux system? Is this recommended approach, or should I convert this app to war and install it into Tomcat?
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Sharing src/test classes between modules in a multi-module maven project
I have a multi-module Maven project. For the sake of this example, consider two modules:
2 Answers
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How to set the context path of a web application in Tomcat 7.0
I know that I can rename my webapp (or it's WAR file) to ROOT but this is a terrible way to do it, IMHO. Now I checked out the tomcat doc & it says
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Understanding typedefs for function pointers in C
...ays been a bit stumped when I read other peoples' code which had typedefs for pointers to functions with arguments. I recall that it took me a while to get around to such a definition while trying to understand a numerical algorithm written in C a while ago. So, could you share your tips and thought...
Open a file with Notepad in C#
...tart().
The simplest example:
Process.Start("notepad.exe", fileName);
More Generic Approach:
Process.Start(fileName);
The second approach is probably a better practice as this will cause the windows Shell to open up your file with it's associated editor. Additionally, if the file specified do...
Invoke-WebRequest, POST with parameters
...s in a hash table and pass them like this:
$postParams = @{username='me';moredata='qwerty'}
Invoke-WebRequest -Uri http://example.com/foobar -Method POST -Body $postParams
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How to get GET (query string) variables in Express.js on Node.js?
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In Express it's already done for you and you can simply use req.query for that:
var id = req.query.id; // $_GET["id"]
Otherwise, in NodeJS, you can access req.url and the builtin url module to url.parse it manually:
var url = require('url');
var url_part...
Right HTTP status code to wrong input
What is optimal HTTP response Code when not reporting 200 (everything OK) but error in input?
6 Answers
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