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How to send email to multiple recipients using python smtplib?
... this script. I was having a problem to send an email from a python script and with this piece of code, i can now send the email.
– fear_matrix
Jul 14 '15 at 10:36
7
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AWK: Access captured group from line pattern
If I have an awk command
6 Answers
6
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Why does document.querySelectorAll return a StaticNodeList rather than a real Array?
...n't just do document.querySelectorAll(...).map(...) even in Firefox 3.6, and I still can't find an answer, so I thought I'd cross-post on SO the question from this blog:
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Configuring Log4j Loggers Programmatically
...ith
Logger.getRootLogger().getLoggerRepository().resetConfiguration();
and start with adding your own. You need log4j in the classpath of course for this to work.
Remark:
You can take any Logger.getLogger(...) you like to add appenders. I just took the root logger because it is at the bottom of...
'size_t' vs 'container::size_type'
Is there is a difference between size_t and container::size_type ?
3 Answers
3
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assign multiple variables to the same value in Javascript
... You may want to comment how the behavior will differ primitive types and reference types when assigning values the way you suggest.
– Steven Wexler
Jun 7 '13 at 4:31
27
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Ignoring new fields on JSON objects using Jackson [duplicate]
...ng Jackson JSON library to convert some JSON objects to POJO classes on an android application. The problem is, the JSON objects might change and have new fields added while the application is published, but currently it will break even when a simple String field is added, which can safely be ignore...
presentViewController and displaying navigation bar
I have a view controller hierarchy and the top-most controller is displayed as a modal and would like to know how to display the navigation bar when using
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What is __main__.py?
...hat is the __main__.py file for, what sort of code should I put into it, and when should I have one?
5 Answers
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How many random elements before MD5 produces collisions?
... quintillion 374 quadrillion 607 trillion 431 billion 768 million 211 thousand 456.
However if you keep all the hashes then the probability is a bit higher thanks to birthday paradox. To have a 50% chance of any hash colliding with any other hash you need 264 hashes. This means that to get a collis...