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Each for object? [duplicate]
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A javascript Object does not have a standard .each function. jQuery provides a function. See http://api.jquery.com/jQuery.each/ The below should work
$.each(object, function(index, value) {
console.log(value);
});
Another option would be to use vanilla Ja...
Unable to import a module that is definitely installed
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I have run into this many times and I think I just discovered the reason: umask is passed through sudo, so if your personal umask is tight and you use sudo for the install, the files and directories will be over-restricted. If you simply su first and then...
What's an Aggregate Root?
... concept of an Aggregate Root keeps coming up. When searching both the web and Stack Overflow for help with what an aggregate root is, I keep finding discussions about them and dead links to pages that are supposed to contain base definitions.
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What is a “bundle” in an Android application
What is a bundle in an Android application? When to use it?
12 Answers
12
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cannot download, $GOPATH not set
...ults to $HOME/go, but you may still find this useful if you want to understand the GOPATH layout, customize it, etc.]
The official Go site discusses GOPATH and how to lay out a workspace directory.
export GOPATH="$HOME/your-workspace-dir/" -- run it in your shell, then add it to ~/.bashrc or equiv...
node.js fs.readdir recursive directory search
...ctory search using fs.readdir? I realise that we could introduce recursion and call the read directory function with the next directory to read, but am a little worried about it not being async...
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Maximum execution time in phpMyadmin
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You can use code formatting to make it clear what is code and what is not as well :)
– span
Dec 13 '12 at 11:07
26
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Create array of regex matches
...an the below if you can assume Java >= 9)
You need to create a matcher and use that to iteratively find matches.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
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List<String> allMatches = new ArrayList<String>();
Matcher m = Pattern.compile("your regular ex...
Can you remove elements from a std::list while iterating through it?
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You have to increment the iterator first (with i++) and then remove the previous element (e.g., by using the returned value from i++). You can change the code to a while loop like so:
std::list<item*>::iterator i = items.begin();
while (i != items.end())
{
bool isA...
How to get object length [duplicate]
...to make sure that you're only counting properties from the object literal, and not properties it "inherits" from its prototype.
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