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Moving decimal places over in a double
...ut.println(new BigDecimal(x));
prints:
0.100000000000000005551115123125782702118158340454101562
12.339999999999999857891452847979962825775146484375
In short, rounding is unavoidable for sensible answers in floating point whether you are doing this explicitly or not.
Note: x / 100 and x * 0.0...
C#位运算符（C#按位与、按位或 等） - 更多技术 - 清泛网 - 专注C/C++及内核技术
...进行位逻辑非运算，结果等于10101010。用十进制表示就是~85等于176。
2、位逻辑与运算
位逻辑与运算将两个运算对象按位进行与运算。与运算的规则：1与1等于1，1与0等于0。
比如：10010001（二进制）&11110000等于10010000（二进...
Selecting the first “n” items with jQuery
... thefoxrocks
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answered Dec 8 '09 at 8:42
istrubleistruble
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Pelican 3.3 pelican-quickstart error “ValueError: unknown locale: UTF-8”
...asically, add some lines to your ~/.bash_profile:
export LC_ALL=en_US.UTF-8
export LANG=en_US.UTF-8
There is an outstanding bug report related to this issue. It appears that Python makes some assumptions about the format of locale names that aren't universally valid. Explicitly setting these en...
How do I convert a Java 8 IntStream to a List?
...
Basil Bourque
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answered May 15 '14 at 9:48
Ian RobertsIa...
Select first 4 rows of a data.frame in R
...
Eduardo LeoniEduardo Leoni
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...
GridLayout and Row/Column Span Woe
...android:columnCount="9"
android:orientation="horizontal"
android:rowCount="8" >
<Button
android:layout_columnSpan="2"
android:layout_gravity="fill"
android:layout_rowSpan="2"
android:text="1" />
<Button
android:layout_columnSpan="2"
android:layout_gravity="fill_...
Splitting a list into N parts of approximately equal length
...Testing:
>>> chunkIt(range(10), 3)
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
>>> chunkIt(range(11), 3)
[[0, 1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
>>> chunkIt(range(12), 3)
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
...
Remove non-utf8 characters from string
Im having a problem with removing non-utf8 characters from string, which are not displaying properly. Characters are like this 0x97 0x61 0x6C 0x6F (hex representation)
...
Finding all possible combinations of numbers to reach a given sum
..., target, partial + [n])
if __name__ == "__main__":
subset_sum([3,9,8,4,5,7,10],15)
#Outputs:
#sum([3, 8, 4])=15
#sum([3, 5, 7])=15
#sum([8, 7])=15
#sum([5, 10])=15
This type of algorithms are very well explained in the following Standford's Abstract Programming lecture...