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Splitting a list into N parts of approximately equal length
...Testing:
>>> chunkIt(range(10), 3)
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
>>> chunkIt(range(11), 3)
[[0, 1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
>>> chunkIt(range(12), 3)
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
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Determine the data types of a data frame's columns
...r(my.data)
'data.frame': 5 obs. of 4 variables:
$ y : num 1.03 1.599 -0.818 0.872 -2.682
$ x1: int 1 2 3 4 5
$ x2: logi TRUE TRUE FALSE FALSE FALSE
$ X3: Factor w/ 5 levels "a","b","c","d",..: 1 2 3 4 5
@Gavin Simpson's approach is also streamlined, but provides slightly different information...
Re-ordering columns in pandas dataframe based on column name [duplicate]
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edited Dec 18 '18 at 22:57
gcamargo
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What Process is using all of my disk IO
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Aaron Digulla
288k9494 gold badges528528 silver badges757757 bronze badges
answered Jan 28 '09 at 19:40
phresusphres...
Regex to validate date format dd/mm/yyyy
...to take dd/mm/yyyy, dd-mm-yyyy or dd.mm.yyyy.
^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[13-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0...
GridLayout and Row/Column Span Woe
...android:columnCount="9"
android:orientation="horizontal"
android:rowCount="8" >
<Button
android:layout_columnSpan="2"
android:layout_gravity="fill"
android:layout_rowSpan="2"
android:text="1" />
<Button
android:layout_columnSpan="2"
android:layout_gravity="fill_...
How to change the CHARACTER SET (and COLLATION) throughout a database?
...n a table (Mysql). He set it up with Latin collation, when it should be UTF8, and now I have issues. Every record with Chinese and Japan character turn to ??? character.
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How do I convert a Java 8 IntStream to a List?
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Basil Bourque
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answered May 15 '14 at 9:48
Ian RobertsIa...
Select first 4 rows of a data.frame in R
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Eduardo LeoniEduardo Leoni
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How to change the output color of echo in Linux
... msanford made for tput, here is the "ANSI-Rainbow" for (( i = 30; i < 38; i++ )); do echo -e "\033[0;"$i"m Normal: (0;$i); \033[1;"$i"m Light: (1;$i)"; done
– everyman
Jan 28 '16 at 21:28
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