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How to call asynchronous method from synchronous method in C#?
...doesn't need to synchronize back to its context, then you can use Task.WaitAndUnwrapException:
var task = MyAsyncMethod();
var result = task.WaitAndUnwrapException();
You do not want to use Task.Wait or Task.Result because they wrap exceptions in AggregateException.
This solution is only appropriat...
Are there any coding standards for JavaScript? [closed]
What are the established coding standards for JavaScript?
8 Answers
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How to add a “open git-bash here…” context menu to the windows explorer?
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I had a similar issue and I did this.
Step 1 : Type "regedit" in start menu
Step 2 : Run the registry editor
Step 3 : Navigate to HKEY_CURRENT_USER\SOFTWARE\Classes\Directory\Background\shell
Step 4 : Right-click on "shell" and choose New >...
Where is Java's Array indexOf?
I must be missing something very obvious, but I've searched all over and can't find this method.
13 Answers
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Are there pronounceable names for common Haskell operators? [closed]
I'm reading Learn You a Haskell for Great Good , and I never know how to pronounce the Haskell operators. Do they have "real" names? ?
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How do I decode HTML entities in Swift?
I am pulling a JSON file from a site and one of the strings received is:
23 Answers
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Converting user input string to regular expression
I am designing a regular expression tester in HTML and JavaScript. The user will enter a regex, a string, and choose the function they want to test with (e.g. search, match, replace, etc.) via radio button and the program will display the results when that function is run with the specified argument...
What is the most efficient way to store tags in a database?
... what is the most effective way to store tags so that they may be searched and filtered?
7 Answers
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How do I remove the passphrase for the SSH key without having to create a new key?
... I realise now, this is quite painful when you are trying to commit ( Git and SVN ) to a remote location over SSH many times in an hour.
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jQuery.inArray(), how to use it right?
First time I work with jQuery.inArray() and it acts kinda strange.
20 Answers
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