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Why is there no SortedList in Java?
In Java there are the SortedSet and SortedMap interfaces. Both belong to the Java Collections framework and provide a sorted way to access the elements.
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Haskell error parse error on input `='
I'm new to Haskell and after starting ghci I tried:
4 Answers
4
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How to get the nth occurrence in a string?
...n unbounded length input, it needlessly creates an unbounded length array, and then throws most of it away. It would be faster and more efficient just to iteratively use the fromIndex argument to String.indexOf
– Alnitak
Jan 23 '13 at 13:31
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S3 Error: The difference between the request time and the current time is too large
I have error The difference between the request time and the current time is too large when call method amazons3.ListObjects
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What are some alternatives to ReSharper? [closed]
... ReSharper license, but are there any possible alternatives to ReSharper and how would you rate these compared to ReSharper?
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What is the maximum number of characters that nvarchar(MAX) will hold?
... 2 = 1'073'741'822 double-byte characters
1 billion, 73 million, 741 thousand and 822 characters to be precise
in your NVARCHAR(MAX) column (unfortunately, that last half character is wasted...)
Update: as @MartinMulder pointed out: any variable length character column also has a 2 byte overhead...
How can I make console.log show the current state of an object?
In Safari with no add-ons (and actually most other browsers), console.log will show the object at the last state of execution, not at the state when console.log was called.
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Check if Internet Connection Exists with Javascript? [duplicate]
...e from your network, you could do this:
function hostReachable() {
// Handle IE and more capable browsers
var xhr = new ( window.ActiveXObject || XMLHttpRequest )( "Microsoft.XMLHTTP" );
// Open new request as a HEAD to the root hostname with a random param to bust the cache
xhr.open( "HE...
How to get index of object by its property in JavaScript?
...e array is probably the best way. But I would put it in it's own function, and make it a little more abstract:
function findWithAttr(array, attr, value) {
for(var i = 0; i < array.length; i += 1) {
if(array[i][attr] === value) {
return i;
}
}
return -1;
}
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map function for objects (instead of arrays)
...For that matter I wanted to add another solution that returns a new object and leaves the original object as it is:
var myObject = { 'a': 1, 'b': 2, 'c': 3 };
// returns a new object with the values at each key mapped using mapFn(value)
function objectMap(object, mapFn) {
return Object.k...