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Should I use multiplication or division?
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Thanks for the tip on using the time command for benchmarking!
– Edmundito
Oct 22 '08 at 17:11
2
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Java HashMap performance optimization / alternative
...or every object:
public int hashCode() {
// assume that both a and b are sorted
return a[0] + powerOf52(a[1], 1) + powerOf52(b[0], 2) + powerOf52(b[1], 3) + powerOf52(b[2], 4);
}
public static int powerOf52(byte b, int power) {
int result = b;
for (int i = 0; i < p...
Are trailing commas in arrays and objects part of the spec?
Are trailing commas standard in JavaScript, or do most browsers like Chrome and Firefox just tolerate them?
6 Answers
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How do I get whole and fractional parts from double in JSP/Java?
How do I get whole and fractional parts from double in JSP/Java ? If the value is 3.25 then I want to get fractional =.25 , whole = 3
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Looking for a good world map generation algorithm [closed]
I'm working on a Civilization-like game and I'm looking for a good algorithm for generating Earth-like world maps. I've experimented with a few alternatives, but haven't hit on a real winner yet.
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Useful code which uses reduce()? [closed]
...uses reduce() function in python? Is there any code other than the usual + and * that we see in the examples?
24 Answers
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HEAD and ORIG_HEAD in Git
What do these symbols refer to and what do they mean?
4 Answers
4
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javascript find and remove object in array based on key value
...g several approaches on how to find an object in an array, where ID = var, and if found, remove the object from the array and return the new array of objects.
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Maximum and Minimum values for ints
I am looking for minimum and maximum values for integers in python. For eg., in Java, we have Integer.MIN_VALUE and Integer.MAX_VALUE . Is there something like this in python?
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C/C++ maximum stack size of program
...nment variable in the OS. You can then check the stack size with ulimit -s and set it to a new value with for example ulimit -s 16384.
Here's a link with default stack sizes for gcc.
DFS without recursion:
std::stack<Node> dfs;
dfs.push(start);
do {
Node top = dfs.top();
if (top is ...
