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Copying a HashMap in Java
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Maybe i'm not understanding this but I don't need a copy of the map. I need a copy of the class that holds the map. ? There for myObjectListB has to be a class derived from MyojbectsList not a hashmap.
– user691305
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What does $(function() {} ); do?
Sometimes I make a function and call the function later.
5 Answers
5
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Difference between two lists
...Using Except is exactly the right way to go. If your type overrides Equals and GetHashCode, or you're only interested in reference type equality (i.e. two references are only "equal" if they refer to the exact same object), you can just use:
var list3 = list1.Except(list2).ToList();
If you need t...
Is there a benefit to defining a class inside another class in Python?
...Essentially, I have two classes that I'm modeling. A DownloadManager class and a DownloadThread class. The obvious OOP concept here is composition. However, composition doesn't necessarily mean nesting, right?
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How to cancel/abort jQuery AJAX request?
...equest if the previous request is not completed I've to abort that request and make a new request.
8 Answers
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What is the rationale behind having companion objects in Scala?
...eton) for a class is needed? Why would I want to create a class, say Foo and also create a companion object for it?
7 Ans...
Calculating arithmetic mean (one type of average) in Python
Is there a built-in or standard library method in Python to calculate the arithmetic mean (one type of average) of a list of numbers?
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How to version REST URIs
...f that resource? Does REST make a distinction between the representation and the resource?
– Cheeso
Jun 9 '09 at 20:16
1
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Compile Views in ASP.NET MVC
... That way your views have a .designer.cs file generated when you save them and on top of getting compile time errors for you views, they are also precompiled into the assembly (= faster warmup) and Resharper provides some additional help as well.
To use this include the RazorGenerator nuget package...
Can I pass parameters by reference in Java?
...itself which is passed by value, hence it appears to be pass-by-reference (and people often claim that it is). This is not the case, as shown by the following:
Object o = "Hello";
mutate(o)
System.out.println(o);
private void mutate(Object o) { o = "Goodbye"; } //NOT THE SAME o!
Will print Hello...