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Is it possible to view RabbitMQ message contents directly from the command line?
Is it possible to view RabbitMQ message contents directly from the command line?
6 Answers
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Get url parameters from a string in .NET
...that returns NameValueCollection.
Uri myUri = new Uri("http://www.example.com?param1=good&param2=bad");
string param1 = HttpUtility.ParseQueryString(myUri.Query).Get("param1");
Check documentation at http://msdn.microsoft.com/en-us/library/ms150046.aspx
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Open another application from your own (intent)
...e
Finally, create another intent with with category=LAUNCHER, action=MAIN, componentName = new ComponentName(packageName, name) and setFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
Finally, context.startActivity(newIntent)
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Android preferences onclick event
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This works for me with PreferenceFragmentCompatDividers.
– Joseph Lam
Nov 23 '17 at 0:18
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What's the valid way to include an image with no src?
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Best way to parse command line arguments in C#? [closed]
...ut doesn't seem to really support console apps with more than one distinct command well. If you want that, try ManyConsole which builds on NDesk.Options: nuget.org/List/Packages/ManyConsole
– Frank Schwieterman
Aug 27 '11 at 23:34
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fatal: 'origin' does not appear to be a git repository
... edited May 23 '17 at 12:17
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answered Mar 26 '13 at 13:13
VonCVonC
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How to get the anchor from the URL using jQuery?
...ou can use the .indexOf() and .substring(), like this:
var url = "www.aaa.com/task1/1.3.html#a_1";
var hash = url.substring(url.indexOf("#")+1);
You can give it a try here, if it may not have a # in it, do an if(url.indexOf("#") != -1) check like this:
var url = "www.aaa.com/task1/1.3.html#a_1",...
Websocket API to replace REST API?
...isn't the best solution for every application, but I'm convinced that this combination would be exceptionally powerful. I admit that there are some drawbacks, such as losing the ability to cache resources. But I have a feeling the advantages will outweigh them.
I'd be interested in following your ...
Android: Getting a file URI from a content URI?
...putStream(uri) to get an InputStream from a URI.
http://developer.android.com/reference/android/content/ContentResolver.html#openInputStream(android.net.Uri)
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