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Can a for loop increment/decrement by more than one?
Are there other ways to increment a for loop in Javascript besides i++ and ++i ? For example, I want to increment by 3 instead of one.
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Fetch first element which matches criteria
...row the NPE. To prevent that from happening, use orElse() instead of get() and provide a fallback object (like orElse(new Station("dummy", -1)), or store the result of findFirst() in a variable and check it with isEmpty() before calling get()
– ifloop
Jan 24 '1...
How to run Conda?
I installed Anaconda and can run Python, so I assume that I installed it correctly. Following this introductory documentation , I am trying to install Python v3.3, so I am copying and pasting the following line into my console:
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subtract two times in python
I have two datetime.time values, exit and enter and I want to do something like:
9 Answers
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Download File to server from URL
Well, this one seems quite simple, and it is. All you have to do to download a file to your server is:
10 Answers
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Adding List.add() another list
I have an IEnumerable<TravelDetails> and I am trying to add the vales in the for -loop to a List<TravelDetails> . I keep getting the errors.
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Occurrences of substring in a string
...at this might or might not return the result expected. With substring "aa" and string to search "aaa" the number of occurences expected may be one (returned by this code), but may be two as well (in this case you'll need "lastIndex++" instead of "lastIndex += findStr.length()") depending on what you...
Match whole string
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Use the start and end delimiters: ^abc$
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What is the best data type to use for money in C#?
...e. Compared to
floating-point types, the decimal type has more precision and a
smaller range, which makes it appropriate for financial and monetary
calculations.
You can use a decimal as follows:
decimal myMoney = 300.5m;
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Converting int to bytes in Python 3
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That's the way it was designed - and it makes sense because usually, you would call bytes on an iterable instead of a single integer:
>>> bytes([3])
b'\x03'
The docs state this, as well as the docstring for bytes:
>>> help(bytes)
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