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List comprehension vs map

...oints, but sometimes map seems easier to read to me: data = map(str, some_list_of_objects). Some other ones... operator.attrgetter, operator.itemgetter, etc. – Gregg Lind Aug 8 '09 at 16:06 ...
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Get the IP address of the machine

... Then you have other languages which isn't even Latin based character set. The sollution is to not use command tools, as they get deprecated like ifconfig. You should use ip now. The proper way of generate language neutral output is to set LANG environment variable to C, like:...
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Regex: ignore case sensitivity

... does show the correct folders. Any idea why? – alpha_989 Jul 1 '18 at 21:19 Here I am trying to find all the folders ...
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云数据及Firebase组件简介 · App Inventor 2 中文网

...社区 反馈 我要反馈 var _hmt = _hmt || []; (function() { var hm = document.createElement("script"); hm.src = "https://hm.baidu.com/hm.js?8d287b854d737bdc880e8ddeac1b309d"; var s = document.getElementsByTagName("script")[0]; ...
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App Inventor 2 中文网 · 项目指南

... .t_desc { color: #5e91a1; height: 60px; } App Inventor 2 入门教程 超实用入门App教程 ...
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How to get the current date/time in Java [duplicate]

...here's the way to do it: String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(Calendar.getInstance().getTime()); share | improve this answer | follow ...
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Merging objects (associative arrays)

...e: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/assign share | improve this answer | follow | ...
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Remove excess whitespace from within a string

...ve it. If you are dealing with extra spaces within a string consider a preg_replace of multiple whitespaces " "* with a single whitespace " ". Example: $foo = preg_replace('/\s+/', ' ', $foo); share | ...
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switch / pattern matching idea

... of the C# compiler it frequently converts switch statements to dictionary-based jump tables, so there doesn't appear to be a good reason it couldn't support switching on types] share | improve this...
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Why is extending native objects a bad practice?

...nderscore.js is an example of the thing done the right way: var arr = []; _(arr).flatten() // or: _.flatten(arr) // NOT: arr.flatten() share | improve this answer | follow ...