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How do I determine scrollHeight?
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edited Mar 2 at 19:07
Andrii
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answered Mar 13 '13 at 0:59
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Autolayout - intrinsic size of UIButton does not include title insets
...on width is derived from the title width plus the icon width plus the left and right content edge insets.
If a button has both an image and text, they’re centered as a group, with no padding between.
If you add a left content inset, it’s calculated relative to the text, not the text + icon.
If y...
What is a “surrogate pair” in Java?
...mething about surrogate pairs . What is a surrogate pair in this context? And what are low and high surrogates?
7 An...
What is the purpose of the : (colon) GNU Bash builtin?
What is the purpose of a command that does nothing, being little more than a comment leader, but is actually a shell builtin in and of itself?
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runOnUiThread vs Looper.getMainLooper().post in Android
...versus Looper.getMainLooper().post() to execute a task on the UI thread in Android??
1 Answer
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How to determine the number of days in a month in SQL Server?
...henever a valid date is provided without crazy workarounds for niche cases and is far simpler code - I'd highly recommend anyone on T-SQL stick to getting the day component of the eomonth output.
– bsplosion
May 10 '19 at 18:15
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How do I temporarily disable triggers in PostgreSQL?
I'm bulk loading data and can re-calculate all trigger modifications much more cheaply after the fact than on a row-by-row basis.
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How to apply !important using .css()?
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The problem is caused by jQuery not understanding the !important attribute, and as such fails to apply the rule.
You might be able to work around that problem, and apply the rule by referring to it, via addClass():
.importantRule { width: 100px !important; }
$('#el...
Catching multiple exception types in one catch block
...ike a cleaner way to obtain the following functionality, to catch AError and BError in one block:
11 Answers
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Finding # occurrences of a character in a string in Ruby
...host.com".count('www.') is the same as "voyage.localhost.com".count('w.') and since there are no w's and two dots the result is 2.
– steenslag
Feb 12 '14 at 11:17
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