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arrayfun can be significantly slower than an explicit loop in matlab. Why?
...r work inside, you would not notice. But since this computation is memory bandwidth bounded, you do see the loop overhead. And you will even more clearly see the overhead of calling Func1 there.
So what's up with arrayfun? No function inlinig there either, so a lot of overhead. But why so much wor...
Setting up maven dependency for SQL Server
...ernate access to SQL Server database. I set up maven dependencies for it and try to find out SQL Server connector on the same way I know MySql has it.
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C++ preprocessor __VA_ARGS__ number of arguments
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This is actually compiler dependent, and not supported by any standard.
Here however you have a macro implementation that does the count:
#define PP_NARG(...) \
PP_NARG_(__VA_ARGS__,PP_RSEQ_N())
#define PP_NARG_(...) \
PP_ARG_N(__VA_ARGS__)
#...
Common elements in two lists
...tB);
// common now contains only the elements which are contained in listA and listB.
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Hashing a dictionary?
...dictionary is not nested, you could make a frozenset with the dict's items and use hash():
hash(frozenset(my_dict.items()))
This is much less computationally intensive than generating the JSON string or representation of the dictionary.
UPDATE: Please see the comments below, why this approach mi...
Bash if statement with multiple conditions throws an error
I'm trying to write a script that will check two error flags, and in case one flag (or both) are changed it'll echo-- error happened. My script:
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Is there an expression for an infinite generator?
...entinel. However, as int() will always return 0, we can call int() forever and never reach 1. This will in effect produce an infinite list of 0's
– Olsgaard
Apr 14 at 8:47
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What is the use for Task.FromResult in C#
In C# and TPL ( Task Parallel Library ), the Task class represents an ongoing work that produces a value of type T.
6 Ans...
Can a variable number of arguments be passed to a function?
... In a case like this call your "manyArgs" by creating a list called "args" and passing that to manyArgs like this "manyArgs(*args)"
– wilbbe01
Feb 16 '11 at 6:02
4
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What is the difference between include and extend in Ruby?
...correct. However there is more to it than that.
If you have a class Klazz and module Mod, including Mod in Klazz gives instances of Klazz access to Mod's methods. Or you can extend Klazz with Mod giving the class Klazz access to Mod's methods. But also you can extend an arbitrary object with o.exte...