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Quick-and-dirty way to ensure only one instance of a shell script is running at a time

What's a quick-and-dirty way to make sure that only one instance of a shell script is running at a given time? 40 Answers ...
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Why is [1,2] + [3,4] = “1,23,4” in JavaScript?

...d for arrays. What happens is that Javascript converts arrays into strings and concatenates those.   Update Since this question and consequently my answer is getting a lot of attention I felt it would be useful and relevant to have an overview about how the + operator behaves in general also. So, h...
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Counting inversions in an array

... find all inversion pairs such that A[i] > A[j] . I'm using merge sort and copying array A to array B and then comparing the two arrays, but I'm having a difficult time seeing how I can use this to find the number of inversions. Any hints or help would be greatly appreciated. ...
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Difference between `set`, `setq`, and `setf` in Common Lisp?

What is the difference between "set", "setq", and "setf" in Common Lisp? 6 Answers 6 ...
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java.lang.UnsupportedClassVersionError: Bad version number in .class file?

... suggestions on the web indicate that the code was compiled in one version and executed in another version (new on old). However, I only have one version of JRE on my system. If I run the commands: ...
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How to split a string and assign it to variables

In Python it is possible to split a string and assign it to variables: 9 Answers 9 ...
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Is there a difference between YES/NO,TRUE/FALSE and true/false in objective-c?

Simple question really; is there a difference between these values (and is there a difference between BOOL and bool)? A co-worker mentioned that they evaluate to different things in Objective-C, but when I looked at the typedefs in their respective .h files, YES/TRUE/true were all defined as 1 an...
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What is the difference between exit(0) and exit(1) in C?

Can anyone tell me? What is the difference between exit(0) and exit(1) in C language? 11 Answers ...
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~x + ~y == ~(x + y) is always false?

... Assume for the sake of contradiction that there exists some x and some y (mod 2n) such that ~(x+y) == ~x + ~y By two's complement*, we know that, -x == ~x + 1 <==> -1 == ~x + x Noting this result, we have, ~(x+y) == ~x + ~y <==> ~(x+y) + (x+y) == ~x + ~y...
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Convert light frequency to RGB?

... And the Fourmilab article makes the important point that some colours are not representable in RGB (bright oranges being a good example) because you cannot "make" arbitrary colours of light by adding three primary colours tog...