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What do 'lazy' and 'greedy' mean in the context of regular expressions?
Could someone explain these two terms in an understandable way?
12 Answers
12
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What is the effect of extern “C” in C++?
...then link to using the C name.
Since C++ has overloading of function names and C does not, the C++ compiler cannot just use the function name as a unique id to link to, so it mangles the name by adding information about the arguments. A C compiler does not need to mangle the name since you can not ...
How to solve PHP error 'Notice: Array to string conversion in…'
I have a PHP file that tries to echo a $_POST and I get an error, here is the code:
5 Answers
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comparing sbt and Gradle [closed]
I am diving into Scala and noticed sbt. I have been quite happy with Gradle in java/groovy projects, and I know there's a scala plugin for Gradle.
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Are duplicate keys allowed in the definition of binary search trees?
I'm trying to find the definition of a binary search tree and I keep finding different definitions everywhere.
12 Answers
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Should we use Nexus or Artifactory for a Maven Repo?
...odules). We have been storing our external dependencies in source control, and using that to update a local repo.
12 Answer...
Seeking clarification on apparent contradictions regarding weakly typed languages
I think I understand strong typing , but every time I look for examples for what is weak typing I end up finding examples of programming languages that simply coerce/convert types automatically.
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In Python how should I test if a variable is None, True or False
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Don't fear the Exception! Having your program just log and continue is as easy as:
try:
result = simulate(open("myfile"))
except SimulationException as sim_exc:
print "error parsing stream", sim_exc
else:
if result:
print "result pass"
else:
print...
C++ multiline string literal
...le string. "
"The disadvantage is that you have to quote "
"each part, and newlines must be literal as "
"usual.";
The indentation doesn't matter, since it's not inside the quotes.
You can also do this, as long as you take care to escape the embedded newline. Failure to do so, like my first...
Why do function pointer definitions work with any number of ampersands '&' or asterisks '*'?
...foo)() = foo; works: foo is implicitly converted into a pointer to itself and that pointer is assigned to p1_foo.
The unary &, when applied to a function, yields a pointer to the function, just like it yields the address of an object when it is applied to an object. For pointers to ordinary f...
