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NASM x86汇编入门指南 - C/C++ - 清泛网 - 专注C/C++及内核技术
...一篇关于AT&T的汇编入门文章)
3.2 如何安装NASM？
下载地址：http://www.nasm.us/
可以下载源码包或者rpm包，rpm –iUh *.rpm
四、Linux汇编介绍
4.1 DOS和Linux汇编主要不同的地方
DOS汇编中，大部分工作依靠21号中断(int ...
Alphabet range in Python
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This is the easiest way I can figure out:
#!/usr/bin/python3
for i in range(97, 123):
print("{:c}".format(i), end='')
So, 97 to 122 are the ASCII number equivalent to 'a' to and 'z'. Notice the lowercase and the need to put 123, since it will not be included).
In print fu...
ImportError: No module named site on Windows
...This could mess the interpreter, if Python 2.7 is first in the %PATH%, and Python3 is set for PYTHONHOME, for example.
– LM.Croisez
May 6 '16 at 13:45
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Get: TypeError: 'dict_values' object does not support indexing when using python 3.2.3 [duplicate]
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@JessePet: What happens if you open a new Python3 terminal and do {1: 2}.values()? Or d = {1: 2}; print d.values()?
– David Robinson
Jul 2 '13 at 18:24
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Python script to copy text to clipboard [duplicate]
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doesn't seem to work out of the box with python3
– Chase Roberts
Feb 19 '15 at 8:42
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How can I open a Shell inside a Vim Window?
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One thing to look out for: The +python or +python3 requirement for vi can be a killer in some work environments.
– cfi
Oct 29 '15 at 7:26
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How do I get the day of week given a date?
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python3: just change all '/' with '//' in the function above and it will work like a charm.
– chabir
Apr 22 at 15:53
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Python - Create list with numbers between 2 values?
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@BillalBegueradj In Python3, range() returns a generator-like object instead of a list. It's basically the same as xrange() in Python 2. You're right that list comprehension isn't needed. The list() builtin function is easier: list(range(x1, ...
Convert decimal to binary in python [duplicate]
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@Timo lol apparently you are using Python3 just change binary(n/2) to binary(n//2) then you won't get that busload :-)
– Aziz Alto
Feb 7 '18 at 16:42
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Round to 5 (or other number) in Python
...n 2
def myround(x, base=5):
return int(base * round(float(x)/base))
Python3
def myround(x, base=5):
return base * round(x/base)
It is easy to see why the above works. You want to make sure that your number divided by 5 is an integer, correctly rounded. So, we first do exactly that (r...