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Check if a number has a decimal place/is a whole number
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Using modulus will work:
num % 1 != 0
// 23 % 1 = 0
// 23.5 % 1 = 0.5
Note that this is based on the numerical value of the number, regardless of format. It treats numerical strings containing whole numbers with a fixed decimal point the same as intege...
Combining two Series into a DataFrame in pandas
I have two Series s1 and s2 with the same (non-consecutive) indices. How do I combine s1 and s2 to being two columns in a DataFrame and keep one of the indices as a third column?
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python numpy ValueError: operands could not be broadcast together with shapes
In numpy, I have two "arrays", X is (m,n) and y is a vector (n,1)
6 Answers
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Reuse a parameter in String.format?
...of the argument in the argument list. The first argument is referenced by "1$", the second by "2$", etc.
String.format("%1$s %1$s %1$s %1$s %1$s %1$s", hello);
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Execution failed app:processDebugResources Android Studio
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Definition of a Balanced Tree
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124
The constraint is generally applied recursively to every subtree. That is, the tree is only ba...
How can I easily fixup a past commit?
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12 Answers
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How to match a String against string literals in Rust?
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101
You can do something like this:
match &stringthing[..] {
"a" => println!("0"),
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