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How to set the style -webkit-transform dynamically using JavaScript?
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The JavaScript style names are WebkitTransformOrigin and WebkitTransform
element.style.webkitTransform = "rotate(-2deg)";
Check the DOM extension reference for WebKit here.
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count members with jsonpath?
...4 items:
accepted value: [1,2,3,4]
mockMvc.perform(get(API_URL))
.andExpect(jsonPath("$", hasSize(4)));
to test that API returns an object containing 2 members:
accepted value: {"foo": "oof", "bar": "rab"}
mockMvc.perform(get(API_URL))
.andExpect(jsonPath("$.*", hasSize(2)));
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How to subtract a day from a date?
...tion: stackoverflow.com/questions/43092508/…
– JohnAndrews
Mar 29 '17 at 12:10
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in python 3 is...
backbone.js - events, knowing what was clicked
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@roufamatic — because those are really standard JavaScript events, so it's out of the scope of BackboneJS. Those docs does not include reference of HTML nor CSS too.
– skalee
Oct 30 '12 at 7:20
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Is is possible to check if an object is already attached to a data context in Entity Framework?
...eing attached. Calling CreateEntityKey on the context makes sure it's nice and generic and will work even with composite keys with no further coding (because EF can already do that for us!).
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Where does forever store console.log output?
I installed forever and am using it, finding it quite funny.
11 Answers
11
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How to check if click event is already bound - JQuery
...y._data(elem, 'events'), an internal data structure, which is undocumented and therefore not 100% guaranteed to remain stable. This shouldn't, however, be a problem, and the relevant line of the plugin code above can be changed to the following:
var data = jQuery._data(this[0], 'events')[type];
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Should have subtitle controller already set Mediaplayer error Android
...ying a music (or other source), it checks if there is a SubtitleController and shows this message if it's not set.
It doesn't seem to care about if the source you want to play is a music or video. Not sure why he did that.
Short answer: Don't care about this "Exception".
Edit :
Still present in...
How do I check if a type provides a parameterless constructor?
...ou can check if you have a value type using the Type.IsValueType property, and create instances using Activator.CreateInstance(Type);
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Appending to an existing string
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Indeed - and << is also shorter to write AND looks similar to the C++ cout variant. << is beauty!
– shevy
Aug 19 '16 at 18:24
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