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Printing 1 to 1000 without loop or conditionals
Task : Print numbers from 1 to 1000 without using any loop or conditional statements. Don't just write the printf() or cout statement 1000 times.
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Which is a better way to check if an array has more than one element?
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ERROR 2003 (HY000): Can't connect to MySQL server on '127.0.0.1' (111)
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pydot and graphviz error: Couldn't import dot_parser, loading of dot files will not be possible
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Concatenate a vector of strings/character
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Try using an empty collapse argument within the paste function:
paste(sdata, collapse = '')
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Remove all the elements that occur in one list from another
Let's say I have two lists, l1 and l2 . I want to perform l1 - l2 , which returns all elements of l1 not in l2 .
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Declaring variables inside or outside of a loop
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edited Aug 6 '17 at 13:35
answered Jan 10 '12 at 13:12
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getting the screen density programmatically in android?
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