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How to replace all occurrences of a character in string?
What is the effective way to replace all occurrences of a character with another character in std::string ?
15 Answers
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Passing base64 encoded strings in URL
...ed to url-encode it, since base64 strings can contain the "+", "=" and "/" characters which could alter the meaning of your data - look like a sub-folder.
Valid base64 characters are below.
ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=
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angular ng-repeat in reverse
..., 4];
$scope.reverse = function(array) {
var copy = [].concat(array);
return copy.reverse();
}
});
</script>
</head>
<body ng-controller="Ctrl">
<ul>
<li ng-repeat="item in items">{{item}}</li>
</u...
How can I strip first and last double quotes?
... If string is '"' (just one double quote), this will remove the single character. I think this is probably not what is desired, probably Walapa wanted to only remove the double quote if it was matched.
– dbn
Aug 26 '16 at 0:28
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Adding two numbers concatenates them instead of calculating the sum
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I kept making this mistake which always concats: var k += Number(i)
– John Phelps
May 29 '19 at 18:43
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techniques for obscuring sensitive strings in C++
...void this. If for example you are sending the key off to a server, send it character by character, so the whole string is never around. Of course, if you are using it from something like RSA encoding, then this is trickier.
4) Do an ad-hoc algorithm -- on top of all this, add a unique twist or two....
Number of lines in a file in Java
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byte[] c = new byte[1024];
int count = 0;
int readChars = 0;
boolean empty = true;
while ((readChars = is.read(c)) != -1) {
empty = false;
for (int i = 0; i < readChars; ++i) {
if (c[i] == '\n') {
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Why doesn't JavaScript have a last method? [closed]
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i = [].concat(loves).pop(); //corn
icon cat loves popcorn
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import .css file into .less file
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Perfect. This works well when you want to concat some CSS files (e.g. in an ie7.less), but not necessarily process them (e.g. bootstrap-ie7 uses expressions, which LESS doesn't handle well).
– Joe
Jun 26 '14 at 18:56
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jQuery OR Selector?
... @alex: but it won't select the same element twice (which a concatenation operator would). It really is an OR selector because it creates a UNION of two or more sets (whereas AND is an intersection).
– cletus
Feb 15 '10 at 3:59
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