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How Do I Choose Between a Hash Table and a Trie (Prefix Tree)?
...ow about accesing data from one structure vs the other? I'm thinking cache and location
– Horia Toma
Apr 14 '14 at 22:38
9
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How to run multiple Python versions on Windows
I had two versions of Python installed on my machine (versions 2.6 and 2.5). I want to run 2.6 for one project and 2.5 for another.
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Why not infer template parameter from constructor?
... the only point of entry of the class (I am talking about copy constructor and operator=). So suppose you are using your class like this :
MyClass m(string s);
MyClass *pm;
*pm = m;
I am not sure if it would be so obvious for the parser to know what template type is the MyClass pm;
Not sure if ...
Add a tooltip to a div
...
@RayL It isn't standard behavior for a tooltip to be clickable - this blurs links and tooltips, preventing the user from knowing whether a highlighted word will 1) give them more information or 2) take them to another page entirely. In genera...
What is the difference between a regular string and a verbatim string?
I have a trial version of Resharper and it always suggests that I switch regular strings to verbatim strings. What is the difference?
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Why doesn't GCC optimize a*a*a*a*a*a to (a*a*a)*(a*a*a)?
...a,2) by compiling it into a*a , but the call pow(a,6) is not optimized and will actually call the library function pow , which greatly slows down the performance. (In contrast, Intel C++ Compiler , executable icc , will eliminate the library call for pow(a,6) .)
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Break promise chain and call a function based on the step in the chain where it is broken (rejected)
...et's say you have something like the following:
stepOne()
.then(stepTwo, handleErrorOne)
.then(stepThree, handleErrorTwo)
.then(null, handleErrorThree);
To better understand what's happening, let's pretend this is synchronous code with try/catch blocks:
try {
try {
try {
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~x + ~y == ~(x + y) is always false?
...
Assume for the sake of contradiction that there exists some x and some y (mod 2n) such that
~(x+y) == ~x + ~y
By two's complement*, we know that,
-x == ~x + 1
<==> -1 == ~x + x
Noting this result, we have,
~(x+y) == ~x + ~y
<==> ~(x+y) + (x+y) == ~x + ~y...
Eliminate space before \begin{itemize} [closed]
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yes, but sometimes the fight is too much to handle.
– Stefano Borini
Jul 2 '09 at 12:50
30
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Differences between “java -cp” and “java -jar”?
...he difference between running a Java application with java -cp CLASSPATH and java -jar JAR_FILE_PATH ? Is one of them preferred to the other for running a Java application? I mean which one of these ways is more expensive for JVM (according to their machine resources usage)?
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