大约有 44,000 项符合查询结果(耗时:0.0195秒) [XML]
How to select rows that have current day's timestamp?
...e the easiest in my opinion:
SELECT * FROM `table` WHERE `timestamp` like concat(CURDATE(),'%');
share
|
improve this answer
|
follow
|
...
An efficient compression algorithm for short text strings [closed]
...tion you should ask is "what algorithm to compress text strings with these characteristics". For instance, if long repetitions are expected, simple Run-Lengh Encoding might be enough. If you can guarantee that only English words, spaces, punctiation and the occasional digits will be present, then Hu...
How does this print “hello world”?
...01100100100111110111111110111101100011000010101000
The program decodes a character for every 5-bits group, from right to left
00100|01100|10010|01111|10111|11111|01111|01100|01100|00101|01000
d | l | r | o | w | | o | l | l | e | h
5-bit codification
For 5 bits, it is...
Is there any use for unique_ptr with array?
...
here's a reason to not use vector: sizeof(std::vector<char>) == 24; sizeof(std::unique_ptr<char[]>) == 8
– Arvid
Sep 12 '14 at 22:34
15
...
In Java, how do I convert a byte array to a string of hex digits while keeping leading zeros? [dupli
...ffffff" because of sign extension. So one might need to take the last two characters of the returned string.
– Marvo
Jul 27 '12 at 20:55
...
How can I create directory tree in C++/Linux?
...#include "sysstat.h"
typedef struct stat Stat;
static int do_mkdir(const char *path, mode_t mode)
{
Stat st;
int status = 0;
if (stat(path, &st) != 0)
{
/* Directory does not exist. EEXIST for race condition */
if (mkdir(path, mode) != 0 ...
“Invalid JSON primitive” in Ajax processing
...
If I had to write code like that (string concat) to create JSON objects, I would kill myself (figuratively speaking). There has to be a better way.
– PandaWood
Feb 20 '13 at 23:32
...
Remove the first character of a string
I would like to remove the first character of a string.
4 Answers
4
...
How to initialize all members of an array to the same value?
...8(...) STRUCTVAL_32(__VA_ARGS__), STRUCTVAL_16(__VA_ARGS__)
struct Pair { char key[16]; char val[32]; };
struct Pair p_data[] = { STRUCTVAL_48("Key", "Value") };
int a_data[][4] = { STRUCTVAL_48(12, 19, 23, 37) };
macro names are negotiable.
...
