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Why doesn't Java offer operator overloading?
...and one double. There is even the whole pointer arithmetic domain (without casting, you can add to a pointer an integer, but you cannot add two pointers...).
In Java, there is no pointer arithmetic, but someone still found string concatenation without the + operator would be ridiculous enough to ju...
How does virtual inheritance solve the “diamond” (multiple inheritance) ambiguity?
...nheritance diagrams to show the derived classes below the bases. (see "downcast", "upcast")
– peterh - Reinstate Monica
Jul 8 '16 at 20:27
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Select distinct values from a table field
...t('city').distinct()
This one returns a ValuesListQuerySet which you can cast to a list.
You can also add flat=True to values_list to flatten the results.
See also: Get distinct values of Queryset by field
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How to see the CREATE VIEW code for a view in PostgreSQL?
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@elias: just use the version that uses an OID by casting the name to an oid: select pg_get_viewdef('viewname'::regclass, true)
– a_horse_with_no_name
Jan 31 '13 at 20:44
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Why are function pointers and data pointers incompatible in C/C++?
...be converted back to the original function pointer type, using an explicit cast, without loss of information. Note: The ISO C standard does not require this, but it is required for POSIX conformance.
– Jonathan Leffler
Sep 11 '12 at 18:23
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What is an example of the Liskov Substitution Principle?
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A great example illustrating LSP (given by Uncle Bob in a podcast I heard recently) was how sometimes something that sounds right in natural language doesn't quite work in code.
In mathematics, a Square is a Rectangle. Indeed it is a specialization of a rectangle. The "is a" makes you...
How do you create a dropdownlist from an enum in ASP.NET MVC?
...adata);
IEnumerable<TEnum> values = Enum.GetValues(enumType).Cast<TEnum>();
IEnumerable<SelectListItem> items = from value in values
select new SelectListItem
{
Text = GetEnumDescription(value),
Value = value....
vs in Generics
...of the generic class, interface or method. The implication is that you can cast the type/interface/method to an equivalent with a super-type of T.
E.g. ICovariant<out Dog> can be cast to ICovariant<Animal>.
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Adding two Java 8 streams, or an extra element to a stream
...type of Something<? extends T>, not the other way, so it couldn't be cast) Additional .map(identity()) cast <? extends T> to <T>. It happens thanks to mix of java 8 'target types' of method arguments and return types and signature of map() method. Actually it is Function.<T>i...
Why would finding a type's initializer throw a NullReferenceException?
...found at least 3 workaround approaches for fixing the problem:
Simply by casting the Type to _Type inside the Main method:
var cctor = ((_Type)typeof(Test)).TypeInitializer;
Or making sure that approach 1 was used previously inside the method:
var warmUp = ((_Type)typeof(Test)).TypeInitializer;...