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Need to list all triggers in SQL Server database with table name and table's schema
...
Here's one way:
SELECT
sysobjects.name AS trigger_name
,USER_NAME(sysobjects.uid) AS trigger_owner
,s.name AS table_schema
,OBJECT_NAME(parent_obj) AS table_name
,OBJECTPROPERTY( id, 'ExecIsUpdateTrigger') AS isupda...
SQL query to find record with ID not in another table
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Try this
SELECT ID, Name
FROM Table1
WHERE ID NOT IN (SELECT ID FROM Table2)
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Finding duplicate values in a SQL table
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SELECT
name, email, COUNT(*)
FROM
users
GROUP BY
name, email
HAVING
COUNT(*) > 1
Simply group on both of the columns.
Note: the older ANSI standard is to have all non-aggregated columns in the GROUP BY ...
How to comment out a block of Python code in Vim
...to allow me to indent certain lines of code (whether those lines have been selected in visual mode, or n lines above/below current cursor position).
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Remove Trailing Spaces and Update in Columns in SQL Server
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Try
SELECT LTRIM(RTRIM('Amit Tech Corp '))
LTRIM - removes any leading spaces from left side of string
RTRIM - removes any spaces from right
Ex:
update table set CompanyName = LTRIM(RTRIM(CompanyName))
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Hide options in a select list using jQuery
...ave an object with key/value pairs of options I want to hide/remove from a select list.
Neither of the following option selectors work. What am I missing?
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How to find all duplicate from a List? [duplicate]
...d then filter out any of the enumerables that have a Count of <=1, then select their keys to get back down to a single enumerable:
var duplicateKeys = list.GroupBy(x => x)
.Where(group => group.Count() > 1)
.Select(group => group.Key);
...
How to check if a table exists in a given schema
... whether a table (or view) exists, and the current user has access to it?
SELECT EXISTS (
SELECT FROM information_schema.tables
WHERE table_schema = 'schema_name'
AND table_name = 'table_name'
);
The information schema is mainly useful to stay portable across major versions and...
Count work days between two dates
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For workdays, Monday to Friday, you can do it with a single SELECT, like this:
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '2008/10/01'
SET @EndDate = '2008/10/31'
SELECT
(DATEDIFF(dd, @StartDate, @EndDate) + 1)
-(DATEDIFF(wk, @StartDate, @EndDate) *...
Is it possible to style a select box? [closed]
I've got an HTML select box that I need to style. I'd prefer to use just CSS but if I have to I'll use jQuery to fill in the gaps.
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