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Replace values in list using Python [duplicate]
...lace if you want, but it doesn't actually save time:
items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for index, item in enumerate(items):
if not (item % 2):
items[index] = None
Here are (Python 3.6.3) timings demonstrating the non-timesave:
In [1]: %%timeit
...: items = [0, 1, 2, 3, 4,...
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answered Sep 4 '11 at 18:00
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Python - Create list with numbers between 2 values?
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694
Use range. In Python 2.x it returns a list so all you need is:
>>> range(11, 17)
[11, ...
SQL RANK() versus ROW_NUMBER()
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How can I keep my fork in sync without adding a separate remote?
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edited Apr 2 '19 at 13:40
userJT
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answered J...
Insert an element at a specific index in a list and return the updated list
... do b = a[:index] + [obj] + a[index:].
However, another way is:
a = [1, 2, 4]
b = a[:]
b.insert(2, 3)
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