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Set selected option of select box
... code into a $(document).ready:
$(function() {
$("#gate").val('gateway_2');
});
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What does “:=” do?
...
http://en.wikipedia.org/wiki/Equals_sign#In_computer_programming
In computer programming languages, the equals sign typically denotes either a boolean operator to test equality of values (e.g. as in Pascal or Eiffel), which is consistent with the symbol's ...
UIImagePickerController breaks status bar appearance
...olution:
UIImagePickerController* imagePicker = [[UIImagePickerController alloc] init];
imagePicker.delegate = self;
and
- (void)navigationController:(UINavigationController *)navigationController willShowViewController:(UIViewController *)viewController animated:(BOOL)animated
{
[[UIApplica...
VBA - how to conditionally skip a for loop iteration
...iteration. I would suggest a judicious use of Goto as a workaround, especially if this is just a contrived example and your real code is more complicated:
For i = LBound(Schedule, 1) To UBound(Schedule, 1)
If (Schedule(i, 1) < ReferenceDate) Then
PrevCouponIndex = i
Goto Nex...
Sending a message to nil in Objective-C
...I wonder what " sending a message to nil " means - let alone how it is actually useful. Taking an excerpt from the documentation:
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Receiving login prompt using integrated windows authentication
...pted for a login. I have set Windows Authentication to enabled in IIS with all other security types disabled and my application web.config file authentication/authorization is set up as:
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Android Fatal signal 11 (SIGSEGV) at 0x636f7d89 (code=1). How can it be tracked down?
...e NDK documents. Ever since the release NDK-r6, it has provided a utility called ndk-stack.
Following is the content from official NDK documents with the NDK-r9 tar ball.
Overview:
ndk-stack is a simple tool that allows you to filter stack traces as they appear in the output of 'adb logcat' and r...
Java String to SHA1
...g Base64. Apache Commons Codec API 1.4, has this nice utility to take away all the pain. refer here
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Explain Morris inorder tree traversal without using stacks or recursion
... / \
(Y) Z
/ \
C D
(Y) above refers to Y and all of its children, which are omitted for recursion issues. The important part is listed anyway.
Now that the tree has a link back to X, the traversal continues...
A
\
Y
/ \
(A) B
\
X
/ \
(Y)...
Should operator
That's basically the question, is there a "right" way to implement operator<< ?
Reading this I can see that something like:
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