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java.net.ConnectException: localhost/127.0.0.1:8080 - Connection refused
I am using xampp apache server to serve resources to the application from my machine. But i am getting the above error.
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How can I get last characters of a string
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The first solution can be made shorter and faster, see my answer below. However, I do agree with the split and pop idea in this particular situation.
– Terence
Mar 18 '13 at 9:45
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SQL Server: Get data for only the past year
...14 for example as the data coming in only had the year. I was not clear in my comment. Thank you
– PCPGMR
Jan 23 '15 at 15:51
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IDEA: javac: source release 1.7 requires target release 1.7
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@CrazyCoder I changed my pom.xml after changing this once much earlier (was waiting on other incoming changes to the pom), so that sounds like a pretty reasonable explanation. Thanks
– Patrick
Dec 4 '12 at 19...
Table Naming Dilemma: Singular vs. Plural Names [closed]
...want it to look like User.Name instead of Users.Name or worse from some of my old databases tables naming tblUsers.strName which is just confusing in code.
My new rule of thumb is to judge how it will look once it's been converted into an object.
one table I've found that does not fit the new nami...
Installing PG gem on OS X - failure to build native extension
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After two days of headache trying to fix my Rails db following Mavericks upgrade, this fixed it for me, many thanks.
– Deborah
Oct 30 '13 at 20:37
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Foreign key constraints: When to use ON UPDATE and ON DELETE
I'm designing my database schema using MySQL Workbench, which is pretty cool because you can do diagrams and it converts them :P
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Is string in array?
...best way to look in a string[] to see if it contains a element. This was my first shot at it. But perhaps there is something that I am overlooking. The array size will be no larger than 200 elements.
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Check for installed packages before running install.packages() [duplicate]
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Does not work on my linux machine (works fine on my windows machine). Two possible reasons: (1) system.file does not look in all .libPath() locations, and (2) my conda based R installation alters the .libPaths in some way.
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How to version REST URIs
...t it is a different representation rather than a different resource, hence my answer.
– Greg Beech
Jun 9 '09 at 20:24
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