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WCF：使用Array替代List - 更多技术 - 清泛网移动版 - 专注C/C++及内核技术
...你能想象我是多么惊讶地看到服务进程的CPU消耗吗？约400K的Image CPU达到了15-20%。我必须考虑一个更好的方案了。
以下是WCF中duplex channel的结构：
[ServiceContract(CallbackContract = typeof(IServiceCallback),
SessionMode = SessionMode.Required)]
...
WCF：使用Array替代List - 更多技术 - 清泛网 - 专注C/C++及内核技术
...你能想象我是多么惊讶地看到服务进程的CPU消耗吗？约400K的Image CPU达到了15-20%。我必须考虑一个更好的方案了。
以下是WCF中duplex channel的结构：
[ServiceContract(CallbackContract = typeof(IServiceCallback),
SessionMode = SessionMode.Required)]
...
Random float number generation
...need to employ a more advanced method.
This will generate a number from 0.0 to 1.0, inclusive.
float r = static_cast <float> (rand()) / static_cast <float> (RAND_MAX);
This will generate a number from 0.0 to some arbitrary float, X:
float r2 = static_cast <float> (rand()) / ...
Find the max of two or more columns with pandas
...df = pd.DataFrame({"A": [1,2,3], "B": [-2, 8, 1]})
>>> df
A B
0 1 -2
1 2 8
2 3 1
>>> df[["A", "B"]]
A B
0 1 -2
1 2 8
2 3 1
>>> df[["A", "B"]].max(axis=1)
0 1
1 8
2 3
and so:
>>> df["C"] = df[["A", "B"]].max(axis=1)
>>> df
...
In Ruby how do I generate a long string of repeated text?
...
310
str = "0" * 999999
...
How to add a border just on the top side of a UIView
...
202
I consider subclassing UIView and overriding drawRect overkill here. Why not add an extension o...
Assign pandas dataframe column dtypes
...
Since 0.17, you have to use the explicit conversions:
pd.to_datetime, pd.to_timedelta and pd.to_numeric
(As mentioned below, no more "magic", convert_objects has been deprecated in 0.17)
df = pd.DataFrame({'x': {0: 'a', 1: 'b'}...
How many double numbers are there between 0.0 and 1.0?
...e), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that's the number of distinct doubles between 0.5 included and 1.0 excluded, and exactly that many also lie between 1.0 included and 2.0 excluded, and so forth.
Counting the doubles bet...
Which method performs better: .Any() vs .Count() > 0?
...
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edited Nov 20 '08 at 12:51
answered Nov 20 '08 at 12:37
...
Javascript seconds to minutes and seconds
...
To get the number of full minutes, divide the number of total seconds by 60 (60 seconds/minute):
var minutes = Math.floor(time / 60);
And to get the remaining seconds, multiply the full minutes with 60 and subtract from the total seconds:
var seconds = time - minutes * 60;
Now if you also wan...