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Facebook share link without JavaScript
...like the js version , What should I do ? At this moment it is opening in a new tab ! Thanks !
– Sagiruddin Mondal
Nov 25 '13 at 23:29
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Force update of an Android app when a new version is available
...ey do not enter in the app. How can I force users to update the app when a new version becomes available?
19 Answers
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How to loop through all enum values in C#? [duplicate]
... like this
if (typeof(T).BaseType != typeof(Enum))
{
throw new ArgumentException("T must be of type System.Enum");
}
return Enum.GetValues(typeof(T)).Cast<T>();
}
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Git push failed, “Non-fast forward updates were rejected”
...ow away the contents of a just-created remote master branch with something new. This solved my problem. While it isn't the solution for everyone, --force can be helpful.
– Brad
Jan 27 '15 at 2:42
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Microsoft Azure: How to create sub directory in a blob container
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If you use Microsoft Azure Storage Explorer, there is a "New Folder" button that allows you to create a folder in a container.
This is actually a virtual folder:
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How to detect first time app launch on an iPhone
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It will work only for new apps that never submitted before.
– Elad
Jan 3 '17 at 8:10
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How do you do Impersonation in .NET?
...nation are provided in .NET via the System.Security.Principal namespace:
Newer code (.NET 4.6+, .NET Core, etc.) should generally use WindowsIdentity.RunImpersonated, which accepts a handle to the token of the user account, and then either an Action or Func<T> for the code to execute.
Windo...
How to bind an enum to a combobox control in WPF?
...gt; GetAllValuesAndDescriptions(Type t)
{
if (!t.IsEnum)
throw new ArgumentException($"{nameof(t)} must be an enum type");
return Enum.GetValues(t).Cast<Enum>().Select((e) => new ValueDescription() { Value = e, Description = e.Description() }).ToList();
}
}
Next, we cre...
Find a pair of elements from an array whose sum equals a given number
...printSumPairs(int []input, int k){
Map<Integer, Integer> pairs = new HashMap<Integer, Integer>();
for(int i=0;i<input.length;i++){
if(pairs.containsKey(input[i]))
System.out.println(input[i] +", "+ pairs.get(input[i]));
else
pairs.put(...
Cannot convert lambda expression to type 'string' because it is not a delegate type [duplicate]
... identical to the one described in the question, you can consider asking a new question to the community.
– Ryan Kohn
Feb 5 '15 at 19:28
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