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Creating anonymous objects in php
...w stdClass;
$obj->aProperty = 'value';
You can also take advantage of casting an array to an object for a more convenient syntax:
$obj = (object)array('aProperty' => 'value');
print_r($obj);
However, be advised that casting an array to an object is likely to yield "interesting" results fo...
config.assets.compile=true in Rails production, why not?
...or a file in /assets is passed to Sprockets. On the first request for each and every asset it is compiled and cached in whatever Rails is using for cache (usually the filesystem).
On subsequent requests Sprockets receives the request and has to look up the fingerprinted filename, check that the fil...
Generate a random number in the range 1 - 10
...rns the same data type as the input (as stated in the manual). You need to cast the result to an integer: trunc(random() * 20)::int
– a_horse_with_no_name
Oct 5 '11 at 17:35
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How to convert float to int with Java
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why is the typecast needed after Math.round()?
– necromancer
Jun 9 '12 at 1:51
81
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Why do some claim that Java's implementation of generics is bad?
...Wildcarding is generally confusing
Various restrictions due to the above - casting etc
Good:
Wildcarding allows covariance/contravariance to be specified at calling side, which is very neat in many situations
It's better than nothing!
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How do I check if a property exists on a dynamic anonymous type in c#?
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I can't change it, can I cast to ExpendoObject?
– David MZ
Mar 31 '12 at 17:24
add a comment
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Converting java.util.Properties to HashMap
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The efficient way to do that is just to cast to a generic Map as follows:
Properties props = new Properties();
Map<String, String> map = (Map)props;
This will convert a Map<Object, Object> to a raw Map, which is "ok" for the compiler (only warning)....
Java Enum definition
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Your solution has an unchecked cast: return (CHILD) this; Consider adding a getThis() method: protected CHILD getThis() { return this; } See: angelikalanger.com/GenericsFAQ/FAQSections/…
– Roland
Nov 28 '1...
How to determine if a type implements a specific generic interface type
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why not just cast to IBar<SomeClass> and check for null? (I mean casting with 'as' of course)
– Pablo Retyk
Feb 2 '09 at 14:04
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How to convert a Drawable to a Bitmap?
...n a conditional statement to check if it is indeed a BitmapDrawable before casting it: if (d instanceof BitmapDrawable) { Bitmap bitmap = ((BitmapDrawable)d).getBitmap(); }
– Tony Chan
Jul 9 '11 at 1:57
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