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How to convert float to int with Java
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why is the typecast needed after Math.round()?
– necromancer
Jun 9 '12 at 1:51
81
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Double Negation in C++
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I think cast it explicitly with (bool) would be clearer, why use this tricky !!, because it is of less typing?
– Baiyan Huang
Mar 29 '10 at 3:39
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Generate random int value from 3 to 6
...CLARE @maxval TINYINT, @minval TINYINT
select @maxval=24,@minval=5
SELECT CAST(((@maxval + 1) - @minval) *
RAND(CHECKSUM(NEWID())) + @minval AS TINYINT)
And that was taken directly from this link, I don't really know how to give proper credit for this answer.
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Creating anonymous objects in php
...w stdClass;
$obj->aProperty = 'value';
You can also take advantage of casting an array to an object for a more convenient syntax:
$obj = (object)array('aProperty' => 'value');
print_r($obj);
However, be advised that casting an array to an object is likely to yield "interesting" results fo...
static const vs #define
...mpile, though you can wrap an enum into a class with implicit constructor, casting operator and user-defined operators)
each constant's type taken from the enclosing enum, so template <typename T> void f(T) get a distinct instantiation when passed the same numeric value from different enums, a...
Why do some claim that Java's implementation of generics is bad?
...Wildcarding is generally confusing
Various restrictions due to the above - casting etc
Good:
Wildcarding allows covariance/contravariance to be specified at calling side, which is very neat in many situations
It's better than nothing!
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Generate a random number in the range 1 - 10
...rns the same data type as the input (as stated in the manual). You need to cast the result to an integer: trunc(random() * 20)::int
– a_horse_with_no_name
Oct 5 '11 at 17:35
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How do I check if a property exists on a dynamic anonymous type in c#?
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I can't change it, can I cast to ExpendoObject?
– David MZ
Mar 31 '12 at 17:24
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Converting java.util.Properties to HashMap
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The efficient way to do that is just to cast to a generic Map as follows:
Properties props = new Properties();
Map<String, String> map = (Map)props;
This will convert a Map<Object, Object> to a raw Map, which is "ok" for the compiler (only warning)....
Java Enum definition
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Your solution has an unchecked cast: return (CHILD) this; Consider adding a getThis() method: protected CHILD getThis() { return this; } See: angelikalanger.com/GenericsFAQ/FAQSections/…
– Roland
Nov 28 '1...