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Position of least significant bit that is set

... position of the least significant bit that is set in an integer, e.g. for 0x0FF0 it would be 4. 22 Answers ...
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How do I combine a background-image and CSS3 gradient on the same element?

... 1580 Multiple backgrounds! body { background: #eb01a5; background-image: url("IMAGE_URL");...
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How to automatically generate N “distinct” colors?

...tness or saturation, you can distribute the hues like so: // assumes hue [0, 360), saturation [0, 100), lightness [0, 100) for(i = 0; i < 360; i += 360 / num_colors) { HSLColor c; c.hue = i; c.saturation = 90 + randf() * 10; c.lightness = 50 + randf() * 10; addColor(c); } ...
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HTML5: Slider with two inputs possible?

... Jarno 2,60122 gold badges2323 silver badges3939 bronze badges answered Jan 21 '11 at 0:28 Martin BuberlMartin ...
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Move an array element from one array position to another

... +150 If you'd like a version on npm, array-move is the closest to this answer, although it's not the same implementation. See its usage sec...
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How to set a single, main title above all the subplots with Pyplot?

...plotlib.pyplot as plt import numpy as np fig=plt.figure() data=np.arange(900).reshape((30,30)) for i in range(1,5): ax=fig.add_subplot(2,2,i) ax.imshow(data) fig.suptitle('Main title') # or plt.suptitle('Main title') plt.show() ...
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How do you make a HTTP request with C++?

...s of a page (an API) and check the contents to see if it contains a 1 or a 0. Is it also possible to download the contents into a string? ...
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In Typescript, How to check if a string is Numeric

... edited Feb 13 '18 at 14:19 k0pernikus 35.4k4040 gold badges154154 silver badges266266 bronze badges answered May 3 '14 at 6:09 ...
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HTML5 canvas ctx.fillText won't do line breaks?

... Neuron 3,54333 gold badges2323 silver badges4040 bronze badges answered Feb 18 '11 at 14:42 Simon SarrisSimon Sarris 56k121...
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Which is faster in Python: x**.5 or math.sqrt(x)?

... math.sqrt(x) is significantly faster than x**0.5. import math N = 1000000 %%timeit for i in range(N): z=i**.5 10 loops, best of 3: 156 ms per loop %%timeit for i in range(N): z=math.sqrt(i) 10 loops, best of 3: 91.1 ms per loop Using Python 3.6....