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Grid of responsive squares

...t you can code : HTML : <div></div> CSS div { width: 30%; padding-bottom: 30%; /* = width for a square aspect ratio */ } Here is a simple layout example of 3*3 squares grid using the code above. With this technique, you can make any other aspect ratio, here is a table gi...
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How to iterate through two lists in parallel?

... 1437 Python 3 for f, b in zip(foo, bar): print(f, b) zip stops when the shorter of foo or bar...
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How to print a percentage value in python?

...age floating point precision type: >>> print "{0:.0%}".format(1./3) 33% If you don't want integer division, you can import Python3's division from __future__: >>> from __future__ import division >>> 1 / 3 0.3333333333333333 # The above 33% example would could now be w...
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str performance in python

While profiling a piece of python code ( python 2.6 up to 3.2 ), I discovered that the str method to convert an object (in my case an integer) to a string is almost an order of magnitude slower than using string formatting. ...
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How to get a value from a cell of a dataframe?

...row as a Series using iloc, and then the value using the column name: In [3]: sub_df Out[3]: A B 2 -0.133653 -0.030854 In [4]: sub_df.iloc[0] Out[4]: A -0.133653 B -0.030854 Name: 2, dtype: float64 In [5]: sub_df.iloc[0]['A'] Out[5]: -0.13365288513107493 ...
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Finding duplicates in O(n) time and O(1) space

... 13 Answers 13 Active ...
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Difference between '..' (double-dot) and '…' (triple-dot) in range generation?

... | edited Dec 21 '16 at 0:33 answered Mar 13 '12 at 19:48 A...
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Regex how to match an optional character

... You could improve your regex to ^([0-9]{5})+\s+([A-Z]?)\s+([A-Z])([0-9]{3})([0-9]{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])[0-9]{3}([0-9]{4})([0-9]{2})([0-9]{2}) And, since in most regex dialects, \d is the same as [0-9]: ^(\d{5})+\s+([A-Z]?)\s+([A-Z])(\d{3})(\d{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])\d{3}(...
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What does auto do in margin:0 auto?

... answered Jul 3 '10 at 8:05 djdd87djdd87 60.7k2424 gold badges144144 silver badges190190 bronze badges ...
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How to check if a value exists in a dictionary (python)

... 394 >>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'} >>>...