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How to do parallel programming in Python?
...r you. Since we did not pass processes, it will spawn one process for each CPU core on your machine. Each CPU core can execute one process simultaneously.
If you want to map a list to a single function you would do this:
args = [A, B]
results = pool.map(solve1, args)
Don't use threads because th...
Git 工具 - 子模块(submodule)：一个仓库包含另一个仓库 - 开源 & Github -...
...方库，或者你独立开发的，用于多个父项目的库。 现在问题来了：你想要把它们当做两个独立的项 有种情况我们经常会遇到：某个工作中的项目需要包含并使用另一个项目。 也许是第三方库，或者你独立开发的，用于多个父...
What is the function of the push / pop instructions used on registers in x86 assembly?
...uestions/29730/processor-microcode-manipulation-to-change-opcodes
How many CPU cycles are needed for each assembly instruction?
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“register” keyword in C?
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It tells the compiler to try to use a CPU register, instead of RAM, to store the variable. Registers are in the CPU and much faster to access than RAM. But it's only a suggestion to the compiler, and it may not follow through.
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Pulse Secure解决方案 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...ure解决方案概述一段时间以来，企业始终在面对接入控制问题。这个需求始自于扩展企业，在此，远程用户常使用未加管理或不可管理的设备接入关键的局域网...概述
一段时间以来，企业始终在面对接入控制问题。这个需求始...
互联网医疗新格局：顶级医生入场 - 资讯 - 清泛网 - 专注C/C++及内核技术
...不到好医生的原因是，互联网问诊多为“头疼脑热”的小问题，最优秀的医生并不愿意花时间。但顶级医生现在也需要一个分诊机制来获得更高质量的患者。
文/温泉
自2013年下半年以来，因一系列政策利好，互联网医疗行业...
What is the difference between task and thread?
...y only use them if you want to run multiple heavy computations on multiple CPUs. For example, in Windows, a thread weighs 12 KiByte (I think), in Linux, a thread weighs as little as 4 KiByte, in Erlang/BEAM even just 400 Byte. In .NET, it's 1 MiByte!)
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为什么说自媒体到了最危险的时期？ - 资讯 - 清泛网 - 专注C/C++及内核技术
...最主要的几点包括盈利模式，与科技自媒体作者的关系等问题。是非对错暂且不论，在这场争论中，不管是支持的，还是反对甚至泼脏水的，各有各的观点。很多人认真的或若有其事的分析着虎嗅的招股书，有人甚至说虎嗅已经...
What is the global interpreter lock (GIL) in CPython?
...s in Python are only good for blocking I/O; your app will never go above 1 CPU core of processor usage
– Ana Betts
Aug 18 '09 at 15:26
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Execution time of C program
...OCKS_PER_SEC is a constant which is declared in <time.h>. To get the CPU time used by a task within a C application, use:
clock_t begin = clock();
/* here, do your time-consuming job */
clock_t end = clock();
double time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
Note that this retur...