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Why rename synthesized properties in iOS with leading underscores? [duplicate]
...s is an artifact of a previous version of the Objective-C runtime.
Originally, @synthesize was used to create accessors methods, but the runtime still required that instance variables had to be instantiated explicitly:
@interface Foo : Bar {
Baz *_qux;
}
@property (retain) Baz *qux;
@end
@imp...
Is explicitly closing files important?
In Python, if you either open a file without calling close() , or close the file but not using try - finally or the " with " statement, is this a problem? Or does it suffice as a coding practice to rely on the Python garbage-collection to close all files? For example, if one does this:
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Private and Protected Members : C++
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Public members of a class A are accessible for all and everyone.
Protected members of a class A are not accessible outside of A's code, but is accessible from the code of any class derived from A.
Private members of a class A are not accessible outside of A's code, or f...
How to paste over without overwriting register
Does anyone know of a way to paste over a visually selected area without having the selection placed in the default register?
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Django MEDIA_URL and MEDIA_ROOT
... answer below; it is a better solution.
– Thane Brimhall
Apr 6 '16 at 14:14
is this in your app or project urls.py?
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Stack smashing detected
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Stack Smashing here is actually caused due to a protection mechanism used by gcc to detect buffer overflow errors. For example in the following snippet:
#include <stdio.h>
void func()
{
char array[10];
gets(array);
}
int main(int argc,...
CSS table layout: why does table-row not accept a margin?
...ered Jan 2 '10 at 23:42
richardtallentrichardtallent
31.4k1313 gold badges7575 silver badges111111 bronze badges
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How to check if a map contains a key in Go?
...ring) and ok will receive a bool that will be set to true if "foo" was actually present in the map
evaluates ok, which will be true if "foo" was in the map
If "foo" is indeed present in the map, the body of the if statement will be executed and val will be local to that scope.
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Java's L number (long) specification
It appears that when you type in a number in Java, the compiler automatically reads it as an integer, which is why when you type in (long) 6000000000 (not in integer's range) it will complain that 6000000000 is not an integer. To correct this, I had to specify 6000000000L . I just learned abo...
Read file from line 2 or skip header row
... This is fine UNTIL the file is too large to read. This is fine for small files.
– CppLearner
Feb 5 '18 at 2:05
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