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How to send SMS in Java
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if all you want is simple notifications, many carriers support SMS via email; see SMS through E-Mail
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How do I watch a file for changes?
... file you want to watch).
Otherwise, polling will probably be the only really platform-independent option.
Note: I haven't tried any of these solutions.
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REST vs JSON-RPC? [closed]
...ions(HTTP headers + representation). For example:
It's possible (and actually mandatory) to embed links annotated with link relation types which convey meanings of these URIs;
Client implementations do not need to depend on particular procedure names and arguments. Instead, clients depend on messa...
How to instantiate a File object in JavaScript?
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@PA.Buisson I'm not sure if this holds for all cases(it was sufficient for me), but you can use the Blob() constructor instead, as suggested here
– raymondboswel
Jan 23 '17 at 10:07
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Making a request to a RESTful API using python
I have a RESTful API that I have exposed using an implementation of Elasticsearch on an EC2 instance to index a corpus of content. I can query the search by running the following from my terminal (MacOSX):
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List all indexes on ElasticSearch server?
I would like to list all indexes present on an ElasticSearch server. I tried this:
22 Answers
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How to construct a REST API that takes an array of id's for the resources
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If you are passing all your parameters on the URL, then probably comma separated values would be the best choice. Then you would have an URL template like the following:
api.com/users?id=id1,id2,id3,id4,id5
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Are there legitimate uses for JavaScript's “with” statement?
...ous as to how I might make effective use of with , while avoiding its pitfalls.
31 Answers
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How to include route handlers in multiple files in Express?
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Actually, the author (TJ Holowaychuck) gives a better approche: vimeo.com/56166857
– avetisk
Mar 23 '13 at 9:36
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MQTT物联网协议完全实践指南 · App Inventor 2 中文网
... offsetY = e.clientY - element.offsetTop; return false; // 防止文本选中 }; // 鼠标移动时拖动元素 document.onmousemove = function(e) { if (!isDragging) return; element.style.left = (e.clientX - offsetX) + 'px'; element.style.top = (e....