大约有 47,000 项符合查询结果（耗时：0.0497秒） [XML]
Suppress Scientific Notation in Numpy When Creating Array From Nested List
...print, default False
# tiny med large
a = np.array([1.01e-5, 22, 1.2345678e7]) #notice how index 2 is 8
#digits wide
print(a) #prints [ 0.0000101 22. 12345678. ]
However if you pass in a number greater than 8 characters wide, e...
Using comparison operators in Scala's pattern matching system
...|
edited Sep 2 '11 at 19:05
answered Oct 18 '09 at 16:53
Be...
How to apply a function to two columns of Pandas dataframe
...n [49]: df
Out[49]:
0 1
0 1.000000 0.000000
1 -0.494375 0.570994
2 1.000000 0.000000
3 1.876360 -0.229738
4 1.000000 0.000000
In [50]: def f(x):
....: return x[0] + x[1]
....:
In [51]: df.apply(f, axis=1) #passes a Series object, row-wise
Out[51]:
0 1....
Why is early return slower than else?
...than with_else():
>>> T(lambda : without_else()).repeat()
[0.42015745017874906, 0.3188967452567226, 0.31984281521812363]
>>> T(lambda : with_else()).repeat()
[0.36009842032996175, 0.28962249392031936, 0.2927151355828528]
>>> T(lambda : without_else(True)).repeat()
[0.3170...
How to read a .xlsx file using the pandas Library in iPython?
...
165
I usually create a dictionary containing a DataFrame for every sheet:
xl_file = pd.ExcelFile(fi...
How to access pandas groupby dataframe by key
...
5 Answers
5
Active
...
Create list of single item repeated N times
...eit('itertools.repeat(0, 10)', 'import itertools', number = 1000000)
0.37095273281943264
>>> timeit.timeit('[0] * 10', 'import itertools', number = 1000000)
0.5577236771712819
But wait - it's not a fair test...
>>> itertools.repeat(0, 10)
repeat(0, 10) # Not a list!!!
The fun...
Changing font size and direction of axes text in ggplot2
...
Drew SteenDrew Steen
13.5k1111 gold badges5454 silver badges8484 bronze badges
...
Path to Powershell.exe (v 2.0)
...
175
I believe it's in C:\Windows\System32\WindowsPowershell\v1.0\. In order to confuse the innocent,...