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Calculate difference in keys contained in two Python dictionaries

... 234 You can use set operations on the keys: diff = set(dictb.keys()) - set(dicta.keys()) Here is...
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Can dplyr package be used for conditional mutating?

... 1 & b == 4), 2, ifelse(a == 0 | a == 1 | a == 4 | a == 3 | c == 4, 3, NA))) Added - if_else: Note that in dplyr 0.5 there is an if_else function defined so an alternative would be to replace ifelse with if_else; however, note that since if_else is stricter than ifelse (both leg...
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How to slice an array in Bash

... 317 See the Parameter Expansion section in the Bash man page. A[@] returns the contents of the arr...
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How to test valid UUID/GUID?

... 439 Currently, UUID's are as specified in RFC4122. An often neglected edge case is the NIL UUID, no...
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What is the optimal Jewish toenail cutting algorithm?

...mport ifilter, permutations validseqs = ifilter(isValid, permutations([1,2,3,4,5])) for i in validseqs: print i (1, 3, 5, 2, 4) (1, 4, 2, 5, 3) (2, 4, 1, 3, 5) (2, 4, 1, 5, 3) (2, 5, 3, 1, 4) (3, 1, 4, 2, 5) (3, 1, 5, 2, 4) (3, 5, 1, 4, 2) (3, 5, 2, 4, 1) (4, 1, 3, 5, 2) (4, 2, 5, 1, 3) (4, 2, ...
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Reduce, fold or scan (Left/Right)?

... 3 Answers 3 Active ...
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All combinations of a list of lists

...d itertools.product: >>> import itertools >>> a = [[1,2,3],[4,5,6],[7,8,9,10]] >>> list(itertools.product(*a)) [(1, 4, 7), (1, 4, 8), (1, 4, 9), (1, 4, 10), (1, 5, 7), (1, 5, 8), (1, 5, 9), (1, 5, 10), (1, 6, 7), (1, 6, 8), (1, 6, 9), (1, 6, 10), (2, 4, 7), (2, 4, 8), (2,...
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Print all but the first three columns

...,$i OFS; if(NF) printf "%s",$NF; printf ORS}' ### Example ### $ echo '1 2 3 4 5 6 7' | awk '{for(i=4;i<NF;i++)printf"%s",$i OFS;if(NF)printf"%s",$NF;printf ORS}' | tr ' ' '-' 4-5-6-7 Sudo_O proposes an elegant improvement using the ternary operator NF?ORS:OFS $ echo '1 2 3 4 5 6 7' | aw...
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Base64 length calculation?

...log2(64) = 6). Therefore 4 chars are used to represent 4 * 6 = 24 bits = 3 bytes. So you need 4*(n/3) chars to represent n bytes, and this needs to be rounded up to a multiple of 4. The number of unused padding chars resulting from the rounding up to a multiple of 4 will obviously be 0, 1, 2 or...
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Operation on every pair of element in a list

... 233 Check out product() in the itertools module. It does exactly what you describe. import iterto...