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What is the most efficient way to create a dictionary of two pandas Dataframe columns?
...Speed comparion (using Wouter's method)
In [6]: df = pd.DataFrame(randint(0,10,10000).reshape(5000,2),columns=list('AB'))
In [7]: %timeit dict(zip(df.A,df.B))
1000 loops, best of 3: 1.27 ms per loop
In [8]: %timeit pd.Series(df.A.values,index=df.B).to_dict()
1000 loops, best of 3: 987 us per loop...
Check whether a string matches a regex in JS
... regex.test() if all you want is a boolean result:
console.log(/^([a-z0-9]{5,})$/.test('abc1')); // false
console.log(/^([a-z0-9]{5,})$/.test('abc12')); // true
console.log(/^([a-z0-9]{5,})$/.test('abc123')); // true
...and you could remove the () from your regexp since you've no n...
Pandas aggregate count distinct
...
How about either of:
>>> df
date duration user_id
0 2013-04-01 30 0001
1 2013-04-01 15 0001
2 2013-04-01 20 0002
3 2013-04-02 15 0002
4 2013-04-02 30 0002
>>> df.groupby("date").agg({"duration": np.sum, "user_id...
Is there a way to rename an Xcode 4 scheme?
... |
edited Mar 18 '11 at 0:59
answered Mar 18 '11 at 0:54
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How do I horizontally center a span element inside a div
...fff;
display: inline-block;
/* float:left; remove */
margin: 10px 10px 0 0;
padding: 5px 10px
}
http://jsfiddle.net/Adrift/cePe3/
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SQL query for today's date minus two months
...
290
If you are using SQL Server try this:
SELECT * FROM MyTable
WHERE MyDate < DATEADD(month, -2...
How do I check out a specific version of a submodule using 'git submodule'?
...ing the change to the parent repository.
$ cd submodule
$ git checkout v2.0
Previous HEAD position was 5c1277e... bumped version to 2.0.5
HEAD is now at f0a0036... version 2.0
git-status on the parent repository will now report a dirty tree:
# On branch dev [...]
#
# modified: submodule (n...
fork() branches more than expected?
...llykwallyk
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How can I update my ADT in Eclipse?
... name.
It will list the updates available- which should ideally be adt 20.xx
Eclipse will restart and hopefully everything should work fine for you.
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How to select only the first rows for each unique value of a column
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answered Jan 11 '11 at 20:50
gbngbn
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