大约有 23,000 项符合查询结果(耗时:0.0342秒) [XML]

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Case insensitive string as HashMap key

I would like to use case insensitive string as a HashMap key for the following reasons. 12 Answers ...
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A better similarity ranking algorithm for variable length strings

I'm looking for a string similarity algorithm that yields better results on variable length strings than the ones that are usually suggested (levenshtein distance, soundex, etc). ...
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C# declare empty string array

I need to declare an empty string array and i'm using this code 9 Answers 9 ...
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How do you create different variable names while in a loop? [duplicate]

...e you can; it's called a dictionary: d = {} for x in range(1, 10): d["string{0}".format(x)] = "Hello" >>> d["string5"] 'Hello' >>> d {'string1': 'Hello', 'string2': 'Hello', 'string3': 'Hello', 'string4': 'Hello', 'string5': 'Hello', 'string6': 'Hello', 'string7': 'Hel...
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How to initialize a list of strings (List) with many string values

How is it possible to initialize (with a C# initializer) a list of strings? I have tried with the example below but it's not working. ...
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Inserting string at position x of another string

I have two variables and need to insert string b into string a at the point represented by position . The result I'm looking for is "I want an apple". How can I do this with JavaScript? ...
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Swift - which types to use? NSString or String

...ality is bridged between the native types and the Foundation types. While String and NSString are mostly interchangeable, i.e, you can pass String variables into methods that take NSString parameters and vice versa, some methods seem to not be automatically bridged as of this moment. See this answe...
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YAML Multi-Line Arrays

In YAML , you can easily create multi-line strings . However, I would like the ability to create a multi-line array (mainly for readibility within config files) using the | character. ...
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Any way to replace characters on Swift String?

I am looking for a way to replace characters in a Swift String . 21 Answers 21 ...
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Android: android.content.res.Resources$NotFoundException: String resource ID #0x5

...be, incercari.setText(valIncercari+""); Or incercari.setText(Integer.toString(valIncercari)); share | improve this answer | follow | ...