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How to create a custom string representation for a class object?
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class foo(object):
def __str__(self):
return "representation"
def __unicode__(self):
return u"representation"
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How to exclude certain directories/files from git grep search
... "magic word" exclude was added to pathspecs. So if you want to search for foobar in every file except for those matching *.java you can do:
git grep foobar -- './*' ':(exclude)*.java'
Or using the ! "short form" for exclude:
git grep foobar -- './*' ':!*.java'
Note that in git versions up to ...
Posting a File and Associated Data to a RESTful WebService preferably as JSON
...xyz
Content-Type: image/jpeg
[image data]
[image data]
[image data]
...
--foo_bar_baz--
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Is an array name a pointer?
...its name represents the whole array.
int arr[7];
/* arr used as value */
foo(arr);
int x = *(arr + 1); /* same as arr[1] */
/* arr not used as value */
size_t bytes = sizeof arr;
void *q = &arr; /* void pointers are compatible with pointers to any object */
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How to get current path with query string using Capybara
...rrent_url might contain a port number. E.g. given a current_url of http://foo.com:8888/some/path, current_url[current_host.size..-1] will equal :8888/some/path. Also, behind the scenes current_host does the same sort of URI.parse logic that @nzifnab recommended in the accepted answer.
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CSS Selector “(A or B) and C”?
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If you have this:
<div class="a x">Foo</div>
<div class="b x">Bar</div>
<div class="c x">Baz</div>
And you only want to select the elements which have .x and (.a or .b), you could write:
.x:not(.c) { ... }
but that's convenie...
How does the new automatic reference counting mechanism work?
...: the equivalent of manual cleanup in ARC is manual breaking of cycles, eg foo = nil.
– Douglas
May 11 '12 at 23:42
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What specifically are wall-clock-time, user-cpu-time, and system-cpu-time in UNIX?
...nswered Sep 7 '11 at 14:52
Fred FooFred Foo
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What do (lambda) function closures capture?
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Consider the following code:
x = "foo"
def print_x():
print x
x = "bar"
print_x() # Outputs "bar"
I think most people won't find this confusing at all. It is the expected behaviour.
So, why do people think it would be different when it is done in a ...
Cannot use ref or out parameter in lambda expressions
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And maybe this?
private void Foo()
{
int value;
Bar(out value);
}
private void Bar(out int value)
{
value = 3;
int[] array = { 1, 2, 3, 4, 5 };
var val = value;
int newValue = array.Where(a => a == val).First();
}
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