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Indent multiple lines quickly in vi
... I can't figure out how to navigate it. How do I indent multiple lines quickly in vi?
32 Answers
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Image Processing: Algorithm Improvement for 'Coca-Cola Can' Recognition
One of the most interesting projects I've worked on in the past couple of years was a project about image processing . The goal was to develop a system to be able to recognize Coca-Cola 'cans' (note that I'm stressing the word 'cans', you'll see why in a minute). You can see a sample below, with ...
java.lang.OutOfMemoryError: GC overhead limit exceeded [duplicate]
...20) text entries each. These Strings have all to be collected (without breaking up into smaller amounts) before being submitted to a database.
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SSH configuration: override the default username [closed]
Is it possible to configure ssh to know what my username should be?
6 Answers
6
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How to implement __iter__(self) for a container object (Python)
... answered Oct 26 '10 at 1:04
mikerobimikerobi
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How can I install a local gem?
...rch the current directory first, so if your .gem file is there, it will pick it up. I found it on the gem reference, which you may find handy as well:
gem install will install the named
gem. It will attempt a local
installation (i.e. a .gem file in the
current directory), and if that fails...
Command to get time in milliseconds
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Peter Mortensen
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answered May 14 '13 at 17:00
AlperAlper
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PHP: How to use array_filter() to filter array keys?
The callback function in array_filter() only passes in the array's values, not the keys.
14 Answers
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How do you create a Distinct query in HQL
...e a way to create a Distinct query in HQL. Either by using the "distinct" keyword or some other method. I am not sure if distinct is a valid keywork for HQL, but I am looking for the HQL equivalent of the SQL keyword "distinct".
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Algorithm to generate all possible permutations of a list?
Say I have a list of n elements, I know there are n! possible ways to order these elements. What is an algorithm to generate all possible orderings of this list? Example, I have list [a, b, c]. The algorithm would return [[a, b, c], [a, c, b,], [b, a, c], [b, c, a], [c, a, b], [c, b, a]].
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