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How to force R to use a specified factor level as reference in a regression?

... See the relevel() function. Here is an example: set.seed(123) x <- rnorm(100) DF <- data.frame(x = x, y = 4 + (1.5*x) + rnorm(100, sd = 2), b = gl(5, 20)) head(DF) str(DF) m1 <- lm(y ~ x + b, data = DF) summary(m1) Now alter the factor ...
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How do I fetch a single model in Backbone?

...ers with the hashbang in your URL like so, http://www.mydomain.com/#clocks/123 , but it should work even if you haven't yet. share | improve this answer | follow ...
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ReSharper warns: “Static field in generic type”

...tity{ SomeValue = "Bar" }; var thirdInst = new OtherEntity { OtherValue = 123 }; var fourthInst = new OtherEntity { OtherValue = 456 }; var xmlData1 = firstInst.Serialize(); var xmlData2 = secondInst.Serialize(); var xmlData3 = thirdInst.Serialize(); var xmlData4 = fourthInst.Serialize(); In thi...
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How to remove a TFS Workspace Mapping?

... 123 I ran into the same problem, and was able to fix it by manually deleting all the files in the ...
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What is a “callback” in C and how are they implemented?

... 123 Here is an example of callbacks in C. Let's say you want to write some code that allows regis...
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Batch file: Find if substring is in string (not in a file)

... When this is run in CMD.EXE, we get: C:\DemoDev>y pqrs "abc def pqr 123" got one - pattern not found C:\DemoDev>y pqr "abc def pqr 123" got zero - found pattern share | improve this a...
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Reading binary file and looping over each byte

..., 146, 215, 61, 111, 218, 171, 4, 160, 250, 110, 51, 128, 106, 3, 10, 116, 123, 128, 31, 73, 152, 58, 49, 184, 223, 17, 176, 166, 195, 6, 35, 206, 206, 39, 231, 89, 249, 21, 112, 168, 4, 88, 169, 215, 132, 255, 168, 129, 127, 60, 252, 244, 160, 80, 155, 246, 147, 234, 227, 157, 137, 101, 84, 115, 10...
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Python equivalent of D3.js

...wered Oct 10 '13 at 19:28 sk8asd123sk8asd123 1,3851212 silver badges1313 bronze badges ...
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Basic HTTP authentication with Node and Express 4

...xpress-basic-auth'); app.use(basicAuth({ users: { admin: 'supersecret123' }, challenge: true // <--- needed to actually show the login dialog! })); share | improve this answer ...
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Check if multiple strings exist in another string

... You need to iterate on the elements of a. a = ['a', 'b', 'c'] str = "a123" found_a_string = False for item in a: if item in str: found_a_string = True if found_a_string: print "found a match" else: print "no match found" ...