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How can I share code between Node.js and the browser?
...cation with a JavaScript client (run in the browser) and a Node.js server, communicating using WebSocket.
15 Answers
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NoClassDefFoundError: android.support.v7.internal.view.menu.MenuBuilder
There is an issue with the Android appcompat v7 library on Samsung devices running Android 4.2. I keep getting crashes with the following stack trace in my Developer Console:
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How to run crontab job every week on Sunday
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201
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CSS: 100% width or height while keeping aspect ratio?
...osition: center;
background-repeat: no-repeat;
}
The reference: http://www.w3schools.com/cssref/css3_pr_background-size.asp
And the demo: http://www.w3schools.com/cssref/playit.asp?filename=playcss_background-size
shar...
How do I declare a namespace in JavaScript?
... I made an open source project JUST to address this design problem: github.com/mckoss/namespace.
– mckoss
Mar 18 '11 at 22:32
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How to merge every two lines into one from the command line?
... @elgalu: Because ANSI colors are just a bunch of escape character combinations. Do a hexedit on such an output, to see what you have.
– not2qubit
Feb 5 '14 at 19:02
7
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Difference between git pull and git pull --rebase
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and merges are how they flow back upwards.
For details refer - http://www.derekgourlay.com/archives/428
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How to split a string, but also keep the delimiters?
... empty character before ; or after ;.
Hope this helps.
EDIT Fabian Steeg comments on Readability is valid. Readability is always the problem for RegEx. One thing, I do to help easing this is to create a variable whose name represent what the regex does and use Java String format to help that. Like...
Android List Preferences: have summary as selected value?
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I had to combine this wit manual updating... because summary is not updated when value is changed...
– Renetik
Nov 12 '14 at 12:08
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Remove an item from array using UnderscoreJS
...ove objects from array by object property.
Using underscore.js, you could combine .findWhere with .without:
var arr = [{
id: 1,
name: 'a'
}, {
id: 2,
name: 'b'
}, {
id: 3,
name: 'c'
}];
//substract third
arr = _.without(arr, _.findWhere(arr, {
id: 3
}));
console.l...